Answer:
Carrie has 0.125 more than Larry and Larry has 3/4 more than Harry. Between them Harry, Larry and Carrie have 151. How many does Harry have? Carrie=63, Larry=56, Harry=32.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
there are 13 symbols in slot machines i.e. 1 bar , 2 lemons , 2 bells ,2 plums ,3 cherries , 3 oranges
there are Total of 3 machines
Probability of getting bar in machine is ![\frac{1}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B13%7D)
Probability of getting 3 bar on 3 machine![=\frac{1}{13} \times\frac{1}{13}\times \frac{1}{13}=\frac{1}{2197}=0.0004](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B13%7D%20%5Ctimes%5Cfrac%7B1%7D%7B13%7D%5Ctimes%20%5Cfrac%7B1%7D%7B13%7D%3D%5Cfrac%7B1%7D%7B2197%7D%3D0.0004)
Probability of getting an orange![=\frac{3}{13}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B13%7D)
Probability of getting 3 oranges on 3 machine![=\frac{3}{13} \times\frac{3}{13}\times \frac{3}{13}=\frac{27}{2197}=0.0122](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B13%7D%20%5Ctimes%5Cfrac%7B3%7D%7B13%7D%5Ctimes%20%5Cfrac%7B3%7D%7B13%7D%3D%5Cfrac%7B27%7D%7B2197%7D%3D0.0122)
Probability of getting a Plum![=\frac{2}{13}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B13%7D)
Probability of getting 3 Plums on 3 machine![=\frac{2}{13} \times\frac{2}{13}\times \frac{2}{13}=\frac{8}{2197}=0.0036](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B13%7D%20%5Ctimes%5Cfrac%7B2%7D%7B13%7D%5Ctimes%20%5Cfrac%7B2%7D%7B13%7D%3D%5Cfrac%7B8%7D%7B2197%7D%3D0.0036)
1. 3/1
2. Will be positive. Aka always rational.
3. 3/1 + 3/1 = 6/2 = 3/1
Divide both sides by -3, and replace
with
. Then
![-3x^4+27x^2+1200=0\iff y^2-9y-400=0](https://tex.z-dn.net/?f=-3x%5E4%2B27x%5E2%2B1200%3D0%5Ciff%20y%5E2-9y-400%3D0)
Factorize the quadratic in
to get
![y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25](https://tex.z-dn.net/?f=y%5E2-9y-400%3D%28y%2B16%29%28y-25%29%3D0%5Cimplies%20y%3D-16%2Cy%3D25)
which in turn means
![x^2=-16,x^2=25](https://tex.z-dn.net/?f=x%5E2%3D-16%2Cx%5E2%3D25)
But
for all real
, so we can ignore the first solution. This leaves us with
![x^2=25\implies x=\pm\sqrt{25}=\pm5](https://tex.z-dn.net/?f=x%5E2%3D25%5Cimplies%20x%3D%5Cpm%5Csqrt%7B25%7D%3D%5Cpm5)
If we allow for any complex solution, then we can continue with the solution we ignored:
![x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i](https://tex.z-dn.net/?f=x%5E2%3D-16%5Cimplies%20x%3D%5Cpm%5Csqrt%7B-16%7D%3D%5Cpm%20i%5Csqrt%7B16%7D%3D%5Cpm4i)
For number 1, the median is 8
For number 2, the mode is C.100
And for number 3, the mean is D.410