x + (x + 3) +
= 75
so you will add up all of the x 's but NOT the x^2
2x + 3 +
= 75
Rearrange to put the x^2 in front of 2x
+ 2x + 3 = 75
subtract the 75 from both sides
+ 2x - 72 = 0
Answer:
we don’t have the whole question so we don’t know what amber likes and doesn’t like.
Explanation:
next time include the WHOLE question
The critical points are at x = 1 and x = 4 giving you the intervals (-inf, 1), (1, 4) and (4, inf).
By substituting x values in these 3 intervals, you can see that f'(x) is positive in the first and third intervals and negative in the second interval.
This means that f(x) is increasing in the first and third intervals and decreasing in the second interval.
The answer is D.
9514 1404 393
Answer:
5x +y = 16
Step-by-step explanation:
Given a point and slope, it often works well to start with the point-slope form of the equation for a line:
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
Your point and slope make this ...
y -6 = -5(x -2)
y -6 = -5x +10 . . . . . . eliminate parentheses
5x +y = 16 . . . . . . . . . add 5x+6 to both sides; your standard form equation