3 years ago

A line passes through the points (-4,5) and (1,-5). Write the equation of the line in slope-

Mathematics

1 answer:

sweet [91]3 years ago

4 0

Answer:

y = -2x - 3

Step-by-step explanation:

Slope: (5 - - 5)/(-4 -1) = 10/-5 = -2

y-intercept: 5 - (-2)(-4) = -3

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Read 2 more answers

SOMEONE PLEASE HELP ME!!!

Svetach [21]

$\text{Consider the function}\\
\\
y=6\tan(x/2)-3\\
\\
\text{to find the x-intercepts of the graph of the function, we put y=0.}\\
\text{so we get}\\
\\
6\tan(x/2)-3=0\\
\\
\Rightarrow 6\tan(x/2)=3\\
\\
\Rightarrow \tan(x/2)=\frac{3}{6}\\
\\
\Rightarrow \tan(x/2)=\frac{1}{2}\\
\\
\Rightarrow \frac{x}{2}=\tan^{-1}\left (\frac{1}{2} \right )$

$\Rightarrow \frac{x}{2}\approx 0.4636\\
\\
\text{the period of tangent is }\pi, \text{ so we have}\\
\\
\Rightarrow \frac{x}{2}\approx 0.4636+n\pi\\
\\
\Rightarrow x=2( 0.4636+n\pi)\\ \\
\Rightarrow x=0.9273+2n\pi\\
\\
\text{Hence the x-itnercepts of the function are: }(0.9273+2n\pi,\ 0)$