Solution: We are given:
We know that a usual values of the test scores falls within 2 standard deviation from the mean.
Therefore, the minimum usual test score is:
The maximum usual test score is:
Therefore, the minimum and maximum “usual” values of the test scores are:
65.4 and 90.6
19) The question is, for which n is n^(4t) equal to 16^(2t)
n^4t = n^(2*2t) = (n^2)^2t
so n^2 must be 16, so n=4
20) Fill in what you know:
<span>f(1) = -2f(0)+3 = -4+3 = -1
</span><span>f(2) = -2f(1)+3 = 2 + 3 = 5
</span>
21) The average speed is the total displacement divided by the total time. In this case the total time is easy, it is 5 seconds (from 5 to 10). The displacement will be d(10)-d(5).
d(10) = 0.8*100 = 80
d(5) = 0.8*25 = 20
So average speed is (80-20)/5 = 12
2200(.15)=330.00
2200+330=2530
2530(.07)=177.10
2530+177.30=2707.10
It would be the 4th one as it is a male that is criticizing her intentions.
Answer:
x=16
Step-by-step explanation:
the angle would be 1/2 of the arc so here's the steps
(2)7x+16=18x-32
14x+32=18x-32
+32 +32
14x+64=18x
-14x . -14x
64=4x
64/4=4x/4
x=16