Answer:
Step-by-step explanation:
we have that

Using a graph tool
see the attached figure
The function represent a vertical parabola that open up
the vertex is a minimum-------> is the point (-0.5, -9.3)
The x-intercepts are the points when the y coordinate is equal to zero
The x-intercepts are the points (-3.5, 0) and (2.5, 0)
so
the function cross the negative x-axis at point
therefore, the answer is
(-4, 0) and (-3, 0)
618 hope this helps you have an amazing week
Answer:
The probability is
Step-by-step explanation:
From the question we are told that
The proportion that live with their parents is 
The sample size is n = 125
Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution
i.e

Now the mean is evaluated as



Generally the proportion that are not staying with parents is

= > 
The standard deviation is mathematically evaluated as



Given the n is large then we can use normal approximation to evaluate the probability as follows

Now applying continuity correction

Generally



So for the z - table


Answer:
9.6
Step-by-step explanation:
1.) -21
2.) 5
3.) -20
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