In the problem, how do you get 6,300,000 using the digits 1-7 to create a
seven-digit number that can be rounded to 6,300,000.
We can use the numbers according to the rule of rounding values, 0-4 and
5-9.
Hence the numbers are:
1. 6, 290,000 = 6, 300, 000
2. 6, 310, 000 = 6, 300, 000
Therefore the numbers concerned in the given value is in the place order of
ten thousand which will determine the hundred thousands’ value.
Answer:
7x + 2y + 8
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Answer:
x² + 7x + 12
Step-by-step explanation:
x squared plus 7 x plus 12
pls give brainliest for the answer
So
a be first term and d be common difference
- a+a+2d+a+4d+a+6d+a+9d=17
- 5a+21d=17--(1)
And
- a+d+a+3d+a+5d+a+7d+a+9d=15
- 5a+25d=15--(2)
Eq(1)-Eq(2)
Put in second one
- 5a+25d=15
- a+5d=3
- a+5/2=15
- a=15-5/2
- a=25/2
Is 52 closer to 0 or 100? (since it rounds to the nearest hundreds)
Since 52 is over the halfway point, which is 50, that means its closer to 100
Answer: 100
