1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dezoksy [38]
3 years ago
5

In quadrilateral JKLM, ∠JKL and ∠LMJ are right angles.

Mathematics
1 answer:
deff fn [24]3 years ago
8 0
What's the question?
You might be interested in
Help please!<br> Find perimeter and Area
MatroZZZ [7]

Answer:

P = 70 mi A = 210 mi^2

Step-by-step explanation:

Sides:

a = 29 m

b = 20 m

c = 21 m

Angles:

A = 90 °

B = 43.6028 °

C = 46.3972 °

Other:

P = 70 m

s = 35 m

K = 210 mi^2

r = 6 m

R = 14.5 m

Agenda:

A = angle A

B = angle B

C = angle C

a = side a

b = side b

c = side c

P = perimeter

s = semi-perimeter

K = area

r = radius of inscribed circle

R = radius of circumscribed circle

SSS is Side, Side, Side

Heron’s formula says that if a triangle ABC has sides of lengths a, b, and c opposite the respective angles, and you let the semiperimeter, s, represent half of the triangle’s perimeter, then the area of the triangle is

7 0
2 years ago
With the air conditioner on, the electric bill was $303. With the air conditioner off, the bill was $194. What was the differenc
professor190 [17]

Answer:

<em>$</em><em>1</em><em>0</em><em>9</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>difference</em><em> </em><em>between</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>bills</em>

Step-by-step explanation:

<em>Difference</em><em> </em><em>=</em><em>$</em><em>(</em><em>3</em><em>0</em><em>3</em><em>-</em><em>1</em><em>9</em><em>4</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>$</em><em>1</em><em>0</em><em>9</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em>

6 0
3 years ago
Read 2 more answers
Which choice is the solution for this system ? 2x − 5y = 14 x + 3 2 y = 5
VashaNatasha [74]

Answer:

The required solution is (5.75,-0.5). It can be written as (\frac{11}{4},-\frac{1}{2}).

Step-by-step explanation:

The given equations are

2x-5y=14                       .... (1)

x+\frac{3}{2}y=5            .... (2)

Multiply the equation (2) by 2.

2x+3y=10                     .... (3)

Subtract equation (1) from equation (3).

2x+3y-(2x-5y)=10-14

2x+3y-2x+5y=-4

8y=-4

y=-\frac{1}{2}=-0.5

Put this value in equation (1).

2x-5(-0.5)=14

2x+2.5=14

2x=11.5

x=5.75

Therefore the required solution is (5.75,-0.5). It can be written as (\frac{11}{4},-\frac{1}{2}).

3 0
3 years ago
Which of the following describes a net of the prism
Grace [21]

The answer is C

Explanation; there are 2 triangles and 3 rectangles

7 0
3 years ago
Read 2 more answers
Which of these polynomials will make the following equation true<br><br>​
Amanda [17]
Poop I think good luck but it’s b x2-
512
4 0
3 years ago
Other questions:
  • A 30-mi. stretch of highway has markers every 0.2 mi. The first marker is at the 0.2 mi. mark and the last marker is at the end
    10·1 answer
  • The lines 6y+2=12x+4 and 4y+12=2x-8 are: a) parallel.
    10·1 answer
  • How do u find the area of a regular polygon? And can someone help me with question 2
    7·1 answer
  • What 2 to the power of four (5.2-3.2) divide by 4
    13·2 answers
  • Please help me asap!!
    9·1 answer
  • A rhombus shaped piece of land has diagonal 20cm and 12 cm.find the area of land​
    11·1 answer
  • HELP PLS ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    9·1 answer
  • A local car dealer is advertising a 2-year lease
    12·1 answer
  • I need help it’s due soon and i need help please also i solved one but i need three solved thanksssss
    11·1 answer
  • The measurement of one angle of a right triangle is 61°.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!