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GREYUIT [131]
2 years ago
11

Solve for y: 1/2(4y+6)=4-2(y-6)/3​

Mathematics
2 answers:
gizmo_the_mogwai [7]2 years ago
8 0

Answer:

0.09

Step-by-step explanation:

hope it helps thank you

jekas [21]2 years ago
4 0

Answer:

y = 7/8

Step-by-step explanation:

12y+18=-4y+32

12y+18-18=-4y+32-18

12y=-4y+14

12y+4y=-4y+14+4y

16y=14

16y/16=14/16

y = 7/8

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2 years ago
What is 817x45 in standerd algorithm pls help
sineoko [7]

Answer:

Step-by-step explanation:

  817

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2 years ago
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The measures of two complementary angles are (3y − 1)° and (4y + 7)°. Determine the value of y. (Type number only)
blondinia [14]

Answer:

y = 12

Step-by-step explanation:

Complementary angles sum to 90 , so

3y - 1 + 4y + 7 = 90

7y + 6 = 90 ( subtract 6 from both sides )

7y = 84 ( divide both sides by 7 )

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5 0
2 years ago
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
2 years ago
Please help, thanks! Ok so, you pick a card at random, put it back, and then pick another card at random. There are FIVE cards a
tatyana61 [14]

Answer:

P(x > 1\ and\ x < 2) = \frac{4}{25}

Step-by-step explanation:

Given

S = \{1,2,3,4,5\}

n(S) = 5

Required

P(x > 1\ and\ x < 2)

P(x > 1\ and\ x < 2) is calculated as:

P(x > 1\ and\ x < 2) = P(x > 1) * P(x < 2)

Since it is a probability with replacement, we have:

P(x > 1\ and\ x < 2) = \frac{n(x > 1)}{n(S)} * \frac{n(x < 2)}{n(S)}

For x > 1, we have:

x > 1 = \{2,3,4,5\}\\

n(x > 1) = 4

For x < 2, we have:

x < 2 = \{1\}

n(x < 2) = 1

P(x > 1\ and\ x < 2) = \frac{n(x > 1)}{n(S)} * \frac{n(x < 2)}{n(S)}

becomes

P(x > 1\ and\ x < 2) = \frac{4}{5} * \frac{1}{5}

P(x > 1\ and\ x < 2) = \frac{4}{25}

6 0
2 years ago
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