2 years ago

Solve for y: 1/2(4y+6)=4-2(y-6)/3

Mathematics

2 answers:

gizmo_the_mogwai [7]2 years ago

8 0

Answer:

0.09

Step-by-step explanation:

hope it helps thank you

jekas [21]2 years ago

4 0

Answer:

y = 7/8

Step-by-step explanation:

12y+18=-4y+32

12y+18-18=-4y+32-18

12y=-4y+14

12y+4y=-4y+14+4y

16y=14

16y/16=14/16

y = 7/8

You might be interested in

A women who is 5 feet 5 inches tall is standing near the Space Needle in Seattle, Washington. She casts a 13-inch shadow at the

Varvara68 [4.7K]

The space needle if 605 ft. high

3 0

2 years ago

.nooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

sashaice [31]

Answer: What is this free?

5 0

2 years ago

Read 2 more answers

A towns population went from 25,800 to 42600 what was the percent of change

ivolga24 [154]

About 165.1% increase

8 0

3 years ago

Read 2 more answers

Convert 156% to a decimal

Fofino [41]

Answer:

1.56

Step-by-step explanation:

156 divided by 100

4 0

3 years ago

Read 2 more answers

Find the volume of the wedge-shaped region contained in the cylinder x2 + y2 = 49, bounded above by the plane z = x and below by

fiasKO [112]

$\displaystyle\iiint_R\mathrm dV=\int_{y=-7}^{y=7}\int_{x=-\sqrt{49-y^2}}^{x=0}\int_{z=x}^{z=0}\mathrm dz\,\mathrm dx\,\mathrm dy$

Converting to cylindrical coordinates, the integral is equivalent to

$\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta$
$=-\displaystyle\left(\int_{\theta=\pi/2}^{3\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=7}r^2\,\mathrm dr\right)$
$=\dfrac{2\times7^3}3=\dfrac{686}3$

4 0

3 years ago

Solve for y: 1/2(4y+6)=4-2(y-6)/3​

Solve for y: 1/2(4y+6)=4-2(y-6)/3