All categories

3 years ago

A distribution x is known to have a mean value of 5 and a standard deviation of 5. what is its mean square value (i.e., the expe

cted value of x2)?

Mathematics

1 answer:

telo118 [61]3 years ago

8 0

$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$
$\implies 5^2=\mathbb E(X^2)-5^2$
$\implies\mathbb E(X^2)=50$

You might be interested in

Bill removed the ten of spades and the king of hearts from a deck of standard playing cards and threw them in the trash. There w

AveGali [126]

Answer:

Step-by-step explanation:

2 if you mean 1 of each so it would be 50 cards

3 0

3 years ago

How do I solve question 6 through 8?<br> Solve for me

rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0

2 years ago

Rewrite each expression in the form kkxxnn, where kk is a real number and nn is an integer. Assume x ≠ 0.

labwork [276]

Answer:

The expression will be $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Step-by-step explanation:

We have given the expression $2x^5\times x^{10}$

We have to write this expression in kkxxnn form , here kk is real number and nn is integer

We know the property of exponent that when two function are multiplied thn their exponent are added

So $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Here kk = 2 and nn = 15

7 0

3 years ago

Solve the inequality −x2<4

Sedaia [141]

-------------------
−x * 2 < 4

-2x < 4

x > -4/2

x > -2
-------------------

-------------------
-x² < 4 has no solutions
-------------------

6 0

4 years ago

Please help surface area

mars1129 [50]

Answer:

490

Step-by-step explanation:

3 0

3 years ago