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3 years ago

9

A distribution x is known to have a mean value of 5 and a standard deviation of 5. what is its mean square value (i.e., the expe

cted value of x2)?

1 answer:

telo118 [61]3 years ago

8 0

$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$
$\implies 5^2=\mathbb E(X^2)-5^2$
$\implies\mathbb E(X^2)=50$

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

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<h3>Problem 1</h3>

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・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

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<h3>Problem 3 </h3>

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