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AveGali [126]
3 years ago
9

A distribution x is known to have a mean value of 5 and a standard deviation of 5. what is its mean square value (i.e., the expe

cted value of x2)?
Mathematics
1 answer:
telo118 [61]3 years ago
8 0
\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2
\implies 5^2=\mathbb E(X^2)-5^2
\implies\mathbb E(X^2)=50
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PLEASE HELP WITH QUESTION. I am taking a test right now with little time left.
Gwar [14]
1834 bfc I believe that’s the right answer
8 0
2 years ago
Help!!!!!!!!!!!!!!!!!!!!!!
zhuklara [117]

Answer:

see below

Step-by-step explanation:

9 ^-5 * 9^-3

When multiplying these we ADD the exponents:

9^-5 * 9^-3

= 9^(-5 + -3)

= 9 ^-8

= 1/9^8  Option A


2.    2^14 / 2^7   This is a division so we SUBTRACT the exponents:-

= 2^(14 - 7)  

= 2^7   (answer)

3.    If the triangle is a right angled one then it will obey Pythagoras Theorem so:-

13^ = x^2 + 5&2

x^2 = 13^2 - 5^2

x^2 = 144

x = 12    (answer)


4.   The last choice is a crucial step.

The total area of the triangles is the same in both large squares so  the area of the large  square e^2 = a^2 + b^2 ( the 2 squares in the left side large square).

5 0
3 years ago
What is 1.1428571429 as a what is fraction
polet [3.4K]
11428571429/10000000000 because all you have to do is say the number as a decimal and count the place values
7 0
3 years ago
A. (x+2) (x2 +x+2) + 2(x3 + x2)
hram777 [196]

Answer:

3x³ + 5x² + 4x + 4

Step-by-step explanation:

Given

(x + 2)(x² + x + 2) + 2(x³ + x²)

To expand the product, each term in the second factor is multiplied by each term in the first factor, that is

x(x² + x + 2) + 2(x² + x + 2) + 2(x³ + x²) ← distribute the parenthesis

= x³ + x² + 2x + 2x² + 2x + 4 + 2x³ + 2x² ← collect like terms

= 3x³ + 5x² + 4x + 4

4 0
3 years ago
Please help anyone thank you
Lesechka [4]
Plug in the values for x and y to check.

-6>8-10
-6>-2

Final answer: False
This is because -6<-2. Remember that for negative numbers, the number with the greater absolute value is less.
6 0
3 years ago
Read 2 more answers
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