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____ [38]
3 years ago
15

What is the slope of the line through (-1,8) and (3,-4)?

Mathematics
1 answer:
laila [671]3 years ago
4 0

Hey there!!

How do we find slopes ?

Slope = \frac{y2-y1}{x2-x1}

We are given with two co-ordinates :

(-1,8) and (3,-4)  

Hence, the slope is :

\frac{-4-8}{3+1}

... \frac{-12}{4} = -3

The slope is -3.

Hope my answer helps!

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Do both of them for 50 points
erastovalidia [21]

Answer:

1) 5.44, 2) 3.9

Step-by-step explanation:

1) a/b + 2b - a^2 when a = 1.4 and b = 0.2

plug in the values:

1.4/0.2 + 2(0.2) - (1.4)^2 = 7 + 0.4 - 1.96 = 5.44

2) a[b-2c]^3 - d/e when a = 2, b = -0.75, c = -1, d = 0, e = -12 5/7 (rewritten to -89/7 = 12.71)

again, plug in the values:

2[-0.75-2(-1)]^3 - 0/12.71 = 2[1.25]^3 - 0 = 2[1.95] = 3.9

5 0
3 years ago
Calculate the following:<br> 4 + 6 = 2 x 5 - 3 =
AURORKA [14]

Answer:

10=7

Step-by-step explanation:

6+4=10

2x5=10

10-3=7

Hope this helps :)

7 0
3 years ago
Read 2 more answers
X = 7 + 3y
pogonyaev
<h3>Given Equation:</h3>

x = 7 + 3y

or, x - 3y - 7 = 0 ........ (i)

5x + 6y = 14

or, 5x + 6y - 14 = 0 .........(ii)

<h3>To Find:</h3>

The value of x and y.

<h3>Solution:</h3>

By dividing eq. ii by 2, we get

5/2x + 3y - 7 = 0 ........ (iii)

By adding eq. i and eq. iii, we get

15/2x = 0

or, <u>x = 0</u> ........(iv)

By putting eq.(iv) in eq. (i), we get

0 - 3y - 7 = 0

or, -3y = 7

or, <u>y = </u><u>-</u><u>7/</u><u>3</u>

<h2>Answer: ( 0, -7/3 )</h2>

The value of x and y is 0 and -7/3 respectively.

5 0
3 years ago
Read 2 more answers
Can someone answer this question?
Ber [7]
I hope this helps you

5 0
3 years ago
Read 2 more answers
2) A 1sbag of m&amp;m's contains 12 red m's; 2nd bag of m&amp;m's contains 16 red m's
astra-53 [7]
SOMINE PLSSS ANSWER THIS ONE
4 0
3 years ago
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