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Igoryamba
4 years ago
13

Okay so I NEED help tonight. Please someone I really have to finish this tonight.

Mathematics
1 answer:
nlexa [21]4 years ago
6 0
What do you need to finish
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Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

5 0
4 years ago
Find the solution to the system of equations. Write the solution as an ordered pair.
8_murik_8 [283]

Answer:

(2, 5)

Step-by-step explanation:

View Image

4 0
3 years ago
Read 2 more answers
What is a simplified eCarlotta thinks that 3y + 5y3 is the same as 8y4. Which statement shows that it is NOT the same?Xpression
stira [4]

Questions:

(a) What is a simplified expression for (x + y) – (x – y)?

(b) Carlotta thinks that 3y + 5y^3 is the same as 8y^4. Which statement shows that it is NOT the same?

Answer:

(x + y) - (x - y) =2y

3y + 5y^3 \ne 8y^4

Step-by-step explanation:

Solving (a):

Given

(x + y) - (x - y)

Required

Simplify

(x + y) - (x - y)

Open brackets

(x + y) - (x - y) = x + y - x + y

Collect Like Terms

(x + y) - (x - y) = x - x+ y  + y

(x + y) - (x - y) = y  + y

(x + y) - (x - y) =2y

Solving (b):

Given

3y + 5y^3 and 8y^4

Required

Which expression shows they are not the same

The expression that shows this is:

3y + 5y^3 \ne 8y^4

Take for instance; y=2

Substitute 2 for y in 3y + 5y^3 \ne 8y^4

3*2 + 5*2^3 \ne 8*2^4

Evaluate all exponents

9 + 5*8 \ne 8*16

9 + 40 \ne 128

49 \ne 128

The above expression supports 3y + 5y^3 \ne 8y^4

5 0
3 years ago
The sides of a square-shaped room are 2 meters long. Carla wants to buy carpet to cover the floor of
ch4aika [34]

Answer:the answer is $256

Step-by-step explanation:

I say this because 2 meters is 4 square meters then just multiply 4 by $64 and there is your answer.

3 0
4 years ago
Please answer correctly with a fair explanation, I will give you brainliest.
s2008m [1.1K]

Answer:

5 and 6

Step-by-step explanation:

We know that the square root of 36 is 6, so the square root of 35 must be between 5 and 6 as it is not a perfect square.

4 0
3 years ago
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