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Strike441 [17]
3 years ago
6

A square has an area of 9 cm². What is its side length?

Mathematics
2 answers:
o-na [289]3 years ago
7 0
Hey there!! I believe your answer is 4.5cm
Snezhnost [94]3 years ago
4 0

Answer:

3 cm

Step-by-step explanation:

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Saturated hydrocarbons are relatively unreactive except in the presence of _____.
snow_lady [41]
<span>Answer: high temperatures and oxygen</span>
8 0
3 years ago
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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The
Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

x = 3y

According to the cost we have:

3x + 7y = 6000

Substituting the first in the second equation we have:

3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375

Thus, the concert was 375 adults.

On the other hand we have:

x = 3 (375) = 1125

Thus, the concert was 1125 children.

In total they were:

375 + 1125 = 1500 people

ANswer:

The concert was 1500 people

3 0
3 years ago
Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *
Luda [366]

Answer:

The answer to your question is   \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1          

Step-by-step explanation:

Data

Foci  (-2, 2)  (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

                  2c = 6

                    c = 6/2

                    c = 3

3.- Determine a

                  2a = 10

                    a = 10/2

                    a = 5

4.- Determine b using the Pythagorean theorem

                   a² = b² + c²

-Solve for b

                   b² = a² - c²

                   b² = 5² - 3²

                   b² = 25 - 9

                   b² = 16

                   b = 4

5.- Find the center (1, 2)  From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

                      \frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1

                       \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1                

3 0
3 years ago
Factor Completely 5v^2-5v-100
bogdanovich [222]

5 {v }^{2}  - 5v - 100 \\  = 5( {v}^{2}  - v - 25) \\  = 5({v}^{2}   + 4v - 5v - 20) \\  = 5[v(v + 4) - 5(v + 4)] \\  = 5(v - 5)(v + 4)

4 0
3 years ago
Read 2 more answers
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