An algebraic expression comprises both numbers and variables together with at least one arithmetic operation. To evaluate an algebraic expression you have to substitute each variable with a number and perform the operations included.

HOPE THIS HELPS!

8 0

3 years ago

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Write an equation in point-slope form, y – y1 = m(x – x1), of the line through points (9, –2) and (10, 2). Use (9, –2) as the po

True [87]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& -2~) 
% (c,d)
&&(~ 10 &,& 2~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{10-9}\implies \cfrac{2+2}{10-9}\implies \cfrac{4}{1}\implies 4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=4(x-9)\implies y+2=4(x-9)$

4 0

3 years ago

What is the solution to the equation below?Round your answer to two decimal places.3*In x=9.9

storchak [24]

See photo for solution

8 0

3 years ago

Plotting these two equations on a graph.<br><br> p=6-2q<br> p=4+q

Mekhanik [1.2K]

Put into slope intercept form, y=mx+b where m=slope
p=-2q+6
slope is -2
subsitute values for q and get values for p
q=0, p=6
(q,p)
(0,6)
(1,4)

p=q+4
slope is 1
subsitutte
q=0,p=4
(q,p)
(0,4)
(1,5)

below are the graphs

7 0

3 years ago