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2 years ago

I need help with question 19

Mathematics

1 answer:

Andrej [43]2 years ago

8 0

Answer:

Step-by-step explanation:

Rotating 270 puts you in the 4th quadrant.

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Help! Select all of the potential solution(s) of the equation 2log5x = log54.

Nastasia [14]

Answer:

x = 2

Step-by-step explanation:

2 log₅ x = log₅ 4
2 log₅ x = log₅ 2²
2 log₅ x = 2 log₅ 2
log₅ x = log₅ 2
x = 2

7 0

3 years ago

Which series of transformations will not map figure Q onto itself? (x + 2, y − 2), reflection over y = x − 1 (x − 2, y + 2), ref

raketka [301]

b Step-by-step explanation:

this is super easy

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2 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
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\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

One

lesantik [10]

$\bf \begin{array}{ccll} oz&calories\\ \cline{1-2} 6&90\\ 64&x \end{array}\implies \cfrac{6}{64}=\cfrac{90}{x}\implies \cfrac{3}{32}=\cfrac{90}{x}\implies 3x=2880 \\\\\\ x=\cfrac{2880}{3}\implies x=960$

3 0

3 years ago

Read 2 more answers

2(5x+4)-3x<br>Only for Best users.

OlgaM077 [116]

Answer:

7x+8

Step-by-step explanation:

2(5x+4)-3x

distribute: 10x+8-3x

=7x+8

6 0

2 years ago

Read 2 more answers