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3 years ago

The attractive force that holds atoms or ions together is called mixture . True or false

Chemistry

1 answer:

Masteriza [31]3 years ago

4 0

Answer:

False

Explanation:

The attractive force that holds atoms or ions together is called chemical bond.

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What is the molecular formula of following show how it is done.1 nitric acid 2 Sulphuric acid 3 Methane 4 Potassium oxide 5 Silv

olga2289 [7]

Answer:

1.HNO₃

Nitric acid is a nitrogen oxoacid of formula HNO3 in which the nitrogen atom is bonded to a hydroxy group and by equivalent bonds to the remaining two oxygen atoms.

2.H₂SO₄

3.CH₄

Methane (US: , UK: ) is a chemical compound with the chemical formula CH4 (one atom of carbon and four atoms of hydrogen). It is a group-14 hydride and the simplest alkane and is the main constituent of natural gas.

4.K₂O

5.AgCl

6.CaCO3

Limestone consists of calcium carbonate, which has the chemical formula CaCO3. Limestone exists in sedimentary and crystalline form.

Explanation:

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6 0

3 years ago

a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp

Drupady [299]

Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL$

Putting values in above equation, we get:

$1\times 0.189\times 19.6=1\times M_2\times 25\\\\M_2=0.148$

b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?\\V_1=10mL\\n_2=1\\M_2=0.148\\V_2=34.9mL$

Putting values in above equation, we get:

$3\times M_1\times 10=1\times 0.148\times 34.9\\\\M_1=0.172M$

The concentration of the phosphoric acid solution is 1.172 M

3 0

3 years ago

Suppose that the saturation magnetization Mmax of the ferromagnetic metal nickel is 4.41 × 105 A/m. Calculate the magnetic momen

Lady bird [3.3K]

Answer : The magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

Explanation :

Formula used :

$M_{max}=(\frac{N}{V})\times \mu$

where,

$M_{max}$ = saturation magnetization = $4.41\times 10^5A/m$

N = Avogadro's number = $6.022\times 10^{23}atoms/mol$

V = volume of nickel atom

$\mu$ = magnetic moment

First we have to calculate the volume of nickel atom.

$Density=\frac{Mass}{Volume}$

$8.90g/cm^3=\frac{58.71g/mol}{Volume}$

$Volume=\frac{58.71g}{8.90g/cm^3}$

$Volume=6.59cm^3=6.59\times (100)^3m^3$

Now we have to calculate the magnetic moment of a single nickel atom.

$M_{max}=(\frac{N}{V})\times \mu$

$4.41\times 10^5=(\frac{(6.022\times 10^{23})}{6.59})\times (100^3)\times \mu$

$\mu=4.82\times 10^{-24}Am^2$

Therefore, the magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

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3 years ago

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liubo4ka [24]

Answer:

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4 0

3 years ago

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Balance the redox reaction equation (occurring in acidic solution) and choose the correct coefficients for each reactant and pro

algol13

Balanced chemical reaction:
PbO₂(s) + Sn(s)+ 4H⁺(aq) → Pb²⁺(aq) + Sn²⁺(aq) + 2H₂O(l).
Oxidation half-reaction: Sn → Sn²⁺ + 2e⁻.
Reduction half-reaction: PbO₂ + 4H⁺ + 2e⁻ → Pb²⁺ + 2H₂O.
Net reaction: Sn + PbO₂ + 4H⁺ + 2e⁻ → Sn²⁺ + 2e⁻ + Pb²⁺ + 2H₂O.
Oxidation is increase of oxidation number, reduction is decrease of oxidation number.

6 0

4 years ago