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sweet [91]
3 years ago
9

Is food being digested physical or chemical change??

Chemistry
1 answer:
mario62 [17]3 years ago
5 0
chemical. During the process of digestion, the food is broken down into smaller molecules. The salivary glands present in our mouth helps in the breakdown of the food. In this process, there is a formation of a new substance. Therefore, it is considered to be a chemical change.
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Five hundred (500) milliliters of sodium chloride 0.9% is prescribed to be given over 4 hours using a volumetric pump. What's th
Angelina_Jolie [31]

<u>Given:</u>

Volume of 0.9% NaCl = 500 ml

Time (t) = 4 hrs

<u>To determine:</u>

The infusion rate of NaCl in ml/hr

<u>Explanation:</u>

Based on the information- 500 ml of NaCl is to be given over a time span of 4 hrs

Hence, the volume of NaCl to be administered per hr is:-

= 1 hr * 500 ml/4 hr = 125 ml

Ans: Infusion rate = 125 ml/hr

6 0
4 years ago
Relationship between the variables of Pressure and Temperature of a gas?
pychu [463]

Answer:

The pressure of a given amount of gas is directly proportional to iys absolute temperature provided that that the volume does not change

7 0
3 years ago
What type of reaction produces a precipitate?
Pavlova-9 [17]
The correct answer is C.

Most of the time, double replacements produce one product that is soluble and one that is insoluble

This results in a precipitate within a liquid or aqueous solution

Hope this helps

7 0
4 years ago
Name 4 other gases in the atmosphere besides oxygen and nitrogen
Klio2033 [76]
Carbon Dioxide, water vapor, Argon, and I think neon.
6 0
3 years ago
Read 2 more answers
An intravenous infusion is to contain 15 mEq of potassium ion and 20 mEq of sodium ion in 500 mL of 5% dextrose injection. Using
Studentka2010 [4]

Answer:

To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.

Explanation:

1mEq of sodium are 59mg of NaCl and 1mEq of potassium are 75mg KCl

in intravenous infusion 15 mEq of K are:

15x75mg KCl = 1,125g of KCl

And 20 mEq of Na are:

20x59mg NaCl = 1,18g of NaCl

To supply the potassium ion it is necessary to inject:

1,125g of KCl×\frac{30mL}{6g} =<em> 5,6mL  of 6g/30mL solution</em>

And, to supply the sodium ion it is necessary to inject:

1,18g of NaCl×\frac{100mL}{0,9g} = <em>131,1 mL of 0,9% solution</em>

<em />

I hope it helps!

6 0
4 years ago
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