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-Dominant- [34]
3 years ago
6

A student is working with four different solid substances: sodium calcium copper and iodine. which substance is most likely to b

reak easily into many pieces?​
Chemistry
2 answers:
Alenkasestr [34]3 years ago
5 0

Answer:

iodine

Explanation:

<em>The substance that can break easily from the list of substances is the </em><em>iodine</em><em>.</em>

<u>Iodine exists as a molecular solid and hence, the molecules are held together by weak Van Der Waal's forces. Iodine thus has characteristic properties of typical molecular solids which include being able to be broken into pieces easily (brittle), low melting and boiling points, insolubility in water, among other properties.</u>

The characteristics of iodine are unlike sodium, calcium, and copper that exist as metal which is hard, tough with high tensile strengths.

irakobra [83]3 years ago
3 0

Answer:

the correct answer is iodine

<*> blue missssst <*>

Explanation:

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How many times stronger is ph4 than ph6?
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Answer:

10 times more acidic than pH5 and 100 times more acidic than pH6

Explanation:

6 0
3 years ago
3. In the above molecules, generally the octet rule can not be followed for every atom. When there are too many electrons or two
Roman55 [17]

Answer:

The octet rule is possible in those atoms which has high number of electrons in their shells.

Explanation:

The octet rule is a type of rule in which the atom has 8 electrons in its outermost shell or valance shell. This rule is not possible for hydrogen and helium because there are very less number of electrons and we know that octet rule needed more number of electrons. Only one atom may be hydrogen or helium is affected in the structure is affected in these situations due to presence of less number of electrons in shells.

4 0
3 years ago
Americium-241 is used in some smoke detectors. It is an alpha emitter with a half-life of 432 years. How long will it take in ye
Mariulka [41]

Answer:

319 years

Explanation:

For a radioactive decay we have

N = N₀e^-kt , where:

N= Particles  Remainng after a time t

N₀ = Particles  Initially  present

k = ln 2/ t₁/₂ , t₁/₂ is the half life of the radioactive element (Am-241)

We are given that the half-life is 432 yrs, from this inhformation we can calculate the value of  k which then will be used to calculate the time Am-241 will take to decay to 40% once we realize we are given the ratio N/N₀.

k = ln 2/ 432 yr = 0.693/ 432 yr   = 1.6 x 10⁻³ /yr

N/N₀ =  e^-kt  

N/N₀ = 60 (amount remaining after 40 % has decayed)/100

N/N₀ = 0.60

0.60 = e-^-kt

taking natural log to both sides of the equation to get rid of e:

ln (0.60) = -1.6 x 10⁻³ /yr x  t    ∴   t = - ln (0.60) /1.6 x 10⁻³/ yr

t = 0.51 /1.6 x 10⁻³ yr = 319 yrs

To verify our answer realize that what is being asked is how many years it will take to decay 40 %, and we are told the half life , 50 % decay , is 432 years, so for 40 % we will expect it will take less than that which agrees with our resul of 319 years.

5 0
3 years ago
The relationship between the mass m of a material, its volume V, and its density D is
Mamont248 [21]
D V = m  thst should nbe the answer
6 0
4 years ago
An industrial chemist is studying a sample of an
Natalija [7]

Answer:

the above

Explanation:

heat the metal until it melts

react it with o2

stretch it

react it with acid

5 0
4 years ago
Read 2 more answers
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