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-Dominant- [34]
3 years ago
6

A student is working with four different solid substances: sodium calcium copper and iodine. which substance is most likely to b

reak easily into many pieces?​
Chemistry
2 answers:
Alenkasestr [34]3 years ago
5 0

Answer:

iodine

Explanation:

<em>The substance that can break easily from the list of substances is the </em><em>iodine</em><em>.</em>

<u>Iodine exists as a molecular solid and hence, the molecules are held together by weak Van Der Waal's forces. Iodine thus has characteristic properties of typical molecular solids which include being able to be broken into pieces easily (brittle), low melting and boiling points, insolubility in water, among other properties.</u>

The characteristics of iodine are unlike sodium, calcium, and copper that exist as metal which is hard, tough with high tensile strengths.

irakobra [83]3 years ago
3 0

Answer:

the correct answer is iodine

<*> blue missssst <*>

Explanation:

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Explanation:

they have different mass number but same atomic number

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3 years ago
A chemist adds 0.50L of a 0.485 M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper(II)
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Explanation:

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

               Number of millimoles = Molarity × Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

             Number of millimoles = Molarity × Volume

                                                 = 0.485 M × 500 mL      

                                                 = 242.5

Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.                                      

4 0
3 years ago
The concentration of solutes in a red blood cell is about 2%. Sucrose cannot pass through the membrane, but water and urea can.
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The concentration of HCl can be determined by titration with a primary standard such as Na2CO3 (sodium carbonate). The titration
Masteriza [31]

Answer:

The concentration of HCl is 0.275 M

Explanation:

<u>Step 1:</u> Data given

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Molar mass of Na2CO3 = 105.99 g/mol

Volume of HCl = 35.7 mL

<u>Step 2: </u>The balanced equation:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

CO3(2-) + 2H+ ---> H2O + CO2

<u>Step 3</u>: Calculate moles of Na2CO3

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moles of HCL = 2 * 0.0049 = 0.0098 moles HCl

<u>Step 5:</u> Calculate molarity of HCl

Molarity = number of moles of HCl / Volume (liters)

Molarity = 0.0098 moles / 0.0357 L

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