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3 years ago

15

maya plants 8 flower bulbs in the fall 2 purple 2 red and 4 pink find the probability that the first flower to bloom is pink

1 answer:

Natali5045456 [20]3 years ago

3 0

Hello! So, you have 8 flowers. 2 are purple, 2 are red, and 4 are pink. That means, there are 4/8 or 1/2 Chance that the first flower to bloom will be pink. The probability is 1/2.

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Find the missing side length image below

barxatty [35]

Answer:

40

Step-by-step explanation:

Based on the Proportional Transversal Theorem, the three parallel lines hat intersects the two transversals, divides the transversal lines proportionally.

Therefore, we would have the following ratio:

28/35 = ?/50

Cross multiply

35*? = 50*28

35*? = 1,400

Divide both sides by 35

? = 1400/35

? = 40

4 0

3 years ago

Please help me !!!

kati45 [8]

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27)~3x^2+15x-72=3(x^2+5x-24)=3(x-3)(x+8)\\\\
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5 0

3 years ago

Read 2 more answers

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago

Factor 70q+60. Write your answer as a product with a whole number greater than 1.

faltersainse [42]

Answer:

10(7q + 6)

Step-by-step explanation:

Find the GCF of 70 and 60: 10
Divide each number by 10 (steps shown below)
70q ÷ 10 = 7q
60 ÷ 10 = 6
Re-write the expression with 10: 10(7q + 6)

I hope this helps!

7 0

3 years ago

Which two answers???

Norma-Jean [14]

Answer:

B and D

Step-by-step explanation:

have a nice day and mark me brainliest! :)

6 0

3 years ago