Answer:
AC = 7.12 units
Step-by-step explanation:
A right triangle has two legs and a hypotenuse. The hypotenuse is opposite the right angle. As Angle C is the right angle, then the triangle can be constructed as shown in the picture attached. The sides of the triangle have a relationship known as the Pythagorean Theorem a² + b² = c². In the theorem, the legs of the triangle are a and b while the hypotenuse is c. Substitute a = x, b = x+6, and c = √52. Simplify and solve.
a² + b² = c²
x² + (x+6)² = √52²
x² + x² + 12x + 36 = 52
2x² + 12x - 16 = 0
You can use the quadratic formula to solve by substituting a = 2, b = 12, and c = -16.
The quadratic formula is
.
Substitute and you'll have:


Only 1.12 is a solution since 7.13 will not satisfy the Pythagorean theorem
Side AC is 6 units longer than side BC. This means x = BC and AC = x + 6.
AC = 1.12 + 6 = 7.12
Answer:
a = 4
Step-by-step explanation:
This is a rather famous probability problem.
The easiest way to solve this is to calculate the probability that you WON'T roll a "double 6" (or a twelve) each time you roll the dice. There are 36 ways in which dice rols can appear and only one is a twelve. So, for one roll, the probability that you will NOT get a twelve is (35/36)^n where 35/36 is about .97222222 and n would equal 1 for the first trial. So for your first roll the odds that you WON'T get a 12 is .97222222.
For the second roll we calculate (35/36) to the second power or (35/36)^2 which equals about .945216.
When we get to the 24th roll we calculate (.97222222)^24 which equals 0.508596.
For the 25th roll, we calculate (.97222222)^25 which equals 0.494468. For the first time we have reached a probability which is lower than 50 per cent. That is to say, after 25 rolls, we have reached a point in which the probability is less than 50 per cent that we will NOT roll a twelve.
To phrase this more clearly, after 25 rolls we reach a point where the probability is greater then 50 per cent that you will roll a 12 at least once.
Please go to this page 1728.com/puzzle3.htm and look at puzzle 48. (The last puzzle on the page). An intersting story associated with this probability problem is that in 1952, a gambler named Fat the Butch bet someone $1,000 that he could roll a 12 after 21 throws. (He miscalculated the odds [as we know you need 25 throws] and after several HOURS, he lost $49,000!!!)
Please go that page and it has a link to the Fat the Butch story.
Vertical angles equal eachother
set angle 4 and angle 8 equal to eachother
3x=x+40
-x both sides
2x=40
÷2 both sides
x=20
solve for angle 4
3 (20)
60 B
Answer:
Its 33,44,55.
Step-by-step explanation: