Answer:
V = 15.2 L
Explanation:
STP means that T = 273 K and P = 1 atm.
We use the<em> PV=nRT equation</em> to <u>convert the given liters of oxygen to moles</u>:
- 1 atm * 7.6 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273 K
Now we<u> convert O₂ moles to H₂O moles</u>, using the <em>stoichiometric coefficients</em> of the equation:
- 0.340 mol O₂ * = 0.68 mol H₂O
Finally we use the PV=nRT equation once again to<u> convert 0.68 moles of H₂O to liters</u>:
- 1 atm * V = 0.68 * 0.082 atm·L·mol⁻¹·K⁻¹ * 273 K
Answer:
11. Extinct basically means that in a species, there are no living organisms.
12. Extinct: No living organisms of the species
Endangered: Very few living organism of the species, and are in danger of being extinct
Threatened: The organisms of the species are likely to be endangered in the future.
Extensive properties depend on the amount of substance. The volume of a sample is an extensive property: 1000 grams of water takes up more volume than 10 grams of water. Mass is also an extensive property.
The heat of formation of nitrogen (II) oxide : +91.3 kJ/mol
<h3>Further explanation</h3>
Given
Reaction
N2(g) + O2(g) + 182.6 kJ → 2 NO(g)
Required
The heat of formation
Solution
In the above reaction, the heat of the reaction is located on the reactant side which indicates that the formation of nitric oxide requires heat (endothermic reaction).
In the above reaction the heat required to form 2 moles of NO, so the heat required for each mole is:
+182.6 kJ : 2 = =+91.3 kJ/mol
Answer:
58.44 g of NaCl are needed.
Explanation:
Given data:
Mass of NaCl needed = ?
Volume of solution = 200 mL (200/1000 =0.2 L)
Molarity of solution = 5 M
Solution:
We will solve this problem through molarity formula.
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will put the values.
5 M = moles of solute / 0.2 L
Moles of solute = 5 mol/L × 0.2 L
Moles of solute = 1 mol
Mass of sodium chloride:
Mass = number of moles × molar mass
Mass = 1 mol × 58.44 g/mol
Mass = 58.44 g
Thus, 58.44 g of NaCl needed.