<h3>
Answer:</h3>
1.75 L HNO₃
<h3>
Explanation:</h3>
We are given;
Molarity of HNO₃ as 0.250 M
Mass of NaOH as 17.5 g
Volume of NaOH = 350 mL
We are required to calculate the volume of 0.250 M
We are going to first write the balanced reaction:
NaOH(aq) + HNO₃(aq) → NaNO₃(aq) + H₂O(l)
Then, we calculate the number of moles of NaOH
Moles = Mass ÷ Molar mass
Molar mass of NaOH = 39.997 g/mol
= 17.5 g ÷ 39.997 g/mol
= 0.4375 moles
We can now calculate the number of moles of HNO₃ using the mole ratio from the equation;
Mole ratio of NaOH to HNO₃ is 1 : 1
Therefore, if moles of NaOH are 0.4375 moles then;
Moles of HNO₃ will also be 0.4375 moles
We can now calculate the volume of HNO₃
Morality = Number of moles ÷ Volume
Thus;
Volume = Number of moles ÷ Molarity
= 0.4375 moles ÷ 0.250 M
= 1.75 L
Therefore, the volume of HNO₃ is 1.75 L
