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2 years ago

Please help 4(1 - p) = -4p + 4

Mathematics

2 answers:

erica [24]2 years ago

7 0

4-p=-4p+4

4-p+4p-4

Step-by-step explanation:

that iw the answer

just olya [345]2 years ago

5 0

P€R is the answer because the statement is true for any value of , because both sides are identical.

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A group of four friends goes to the movies. Each friend pays for a ticket, a snack, ana

kvv77 [185]

Answer:4(1.5)

Step-by-step explanation:

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2 years ago

A paddle boat rents for $10 plus $8 per hour. How much does it cost to rent a paddle boat for h hours?

vlabodo [156]

8h + 10 or 10 + 8h

Hope this helps :)

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2 years ago

What is the answer to 2 2/10 - 4/10

telo118 [61]

Answer:

1 4/5 (Proper Fraction)

1 8/10 (Proper Fraction, but Not simplified)

18/10 (Improper Fraction)

Step-by-step explanation:

change to improper fraction

22/10 - 4/10 = 18/10

Simplify

18/10 = 1 8/10

Simplify again

1 4/5

8 0

2 years ago

Read 2 more answers

294 simplify the radicals

MrRissso [65]

7√6 or in decimal form it’s 17.1464819....

4 0

2 years ago

A circle is centered at the point (-7, -1) and passes through the point (8, 7).The radius of the circle is____ units. The point

denis-greek [22]

Answer:

Part 1) The radius of the circle is r=17 units

Part 2) The points (-15,14) and (-15,-16) lies on this circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center of the circle and any point on the circle is equal to the radius of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(-7, -1) and (8, 7)

substitute

$r=\sqrt{(7+1)^{2}+(8+7)^{2}}$

$r=\sqrt{(8)^{2}+(15)^{2}}$

$r=\sqrt{289}$

$r=17\ units$

step 2

Find out the y-coordinate of point (-15,y)

The equation of the circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

substitute the values

$(x+7)^2+(y+1)^2=17^2$

$(x+7)^2+(y+1)^2=289$

Substitute the value of x=-15 in the equation

$(-15+7)^2+(y+1)^2=289$

$64+(y+1)^2=289$

$(y+1)^2=289-64$

$(y+1)^2=225$

square root both sides

$(y+1)=(+/-)15$

$y=-1(+/-)15$

$y=-1(+)15=14$

$y=-1(-)15=-16$

therefore

we have two solutions

point (-15,14) and point (-15,-16)

see the attached figure to better understand the problem

8 0

3 years ago