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GenaCL600 [577]
3 years ago
6

Can anyone help me do this math problem ( dont say dumb awnser to get the points)

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

Answer is -4.45: I owe $8.75. I have 4.3

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Please help. Find tanX
Kruka [31]

Answer:

32/24

Step-by-step explanation:

opposite/ adjacent

5 0
3 years ago
Read 2 more answers
What is the equation for a line passing through (-2,3) and perpendicular to y= -1/2+1 ?
nata0808 [166]

Answer:

y=2x+7

Step-by-step explanation:

<u><em>The correct question is</em></u>

what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2<em>x</em>+1 ?

Remember

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)

The slope of the given line is m=-1/2

so

the opposite reciprocal is m=2

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=2\\point\ (-2,3)

substitute

y-3=2(x+2)

<em>Convert to slope intercept form</em>

y=mx+b

isolate the variable y

y-3=2x+4

y=2x+4+3

y=2x+7

3 0
3 years ago
Solve the system by substitution.<br> 4y =<br> 5x -10y =-50
Trava [24]

Answer:

x = -20 ; y =-5

Step-by-step explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

=>5(x-2y)=-50

=>x-2y=\frac{-50}{5} =-10

(Substituting the value of x from eqn. 1)

=>4y-2y=-10

=>2y=-10

=>y =\frac{-10}{2} =-5

Now, substituting the value of y in eqn. 1 ,

x = 4*(-5)=-20

7 0
2 years ago
Order from least to greatest 0.5, 1/5, 0.35, 12/25, 4/5
sdas [7]
First change them all into either fractions or decimals. Decimals are probably easier though. 1/5 = 0.2; 12/25 = 0.48; 4/5 = 0.8 
Order: 0.2, 0.35, 0.48, 0.5, 0.8
Then you change the decimals that you converted back into the fraction form
Answer: 1/5, 0.35, 12/25, 0.5, 4/5
5 0
3 years ago
you earn a salary of $40,000 per year amd decide to save 20%of your gross pay.you then set a goal of creating a $16,000 emergenc
sveticcg [70]
2 years ( 20% of $40,000 = $8,000)
6 0
2 years ago
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