I'll assume that's an exponent at the end there:
The first derivative gives the velocity. The second derivative gives the acceleration; increasing velocity is the same as positive acceleration. So we want to find when the second derivative is positive.
Let's see if we can use 
to avoid multiplying this out.
That worked; let's do it again:
That's a nice parabola. It's zero or negative for 
so positive everywhere else:
Answer: Increasing velocity when t < 1 or t > 3
Answer: The correct option is B-He left out the place holder under the 4.
Step-by-step explanation:
Consider the provided multiplication.
Jared need to multiply 36.47 with 12
The correct multiplication should be:
36.47
× 12
7294
36470
43764
Now consider the Jared's work he just left out the place holder under the 4.
Because it is not just 1×36.47 it is actually 10×36.47, so he needs to add a zero under the number 4.
Answer:
it would be b for 1 since 7 would be negative and the 3 would be positive
Answer: Scale factor of -1/2
Step-by-step explanation:
B=A*(-2)
A=B/(-2)
A=-(B/2)
A=B*(-1/2)
Scale factor of -1/2
Answer:
90 degrees
Step-by-step explanation:
