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3 years ago

What is the slope of these two points?

Mathematics

2 answers:

Elena-2011 [213]3 years ago

8 0

Answer: the slope to these points is -3

Mashutka [201]3 years ago

3 0

Step-by-step explanation:

do you want to know why this is the right answer ?

first of all, points don't have slopes. but a line connecting these 2 points does.

so, whoever phrased that question showed a remarkable inability of percussion precise language necessary for successful math. and a shame for a math teacher.

so, now back to the why.

the slope of a line is the ratio y/x indicating how many units y changes, when x changes a certain amount of units when going from one point to another.

going from (2, 4) to (1, 7)

x changes by -1 (from 2 to 1),

y changes by +3 (from 4 to 7).

so, the slope of the line connecting these two points is

3/-1 = -3

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Determine the points for the graph of the relation y = -5x -3 using the x-values given in the table

Marina CMI [18]

Answer:

A. Yes. Each x value has only one y value. No x value has 2 different y values.

B. For the table, y is 8 when x is 11.

Plug in the value to determine the y value for the equation.

f(x)= 5(11)-21

f(x)= 55-21

f(x)= 34

Since 34>8, the value of the equation f(x) is greater when x=11.

C. 99=5x-21

120=5x

x=24

Final answer: 24

Step-by-step explanation:

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I hope this helps you

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3 years ago

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kotykmax [81]

Answer:

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Step-by-step explanation:

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3 years ago

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4x+8y=-24 what is this how do i do it

borishaifa [10]

Answer:

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Step-by-step explanation:

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3 years ago

Two cars start out together from the same place. they travel in opposite directions, with one of them traveling 5 miles per hou

Mashutka [201]

<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.

One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
$\boxed{\boxed{ v_{1}=68mph} }$
$\boxed{\boxed{ v_{2}=63mph} }$

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4 years ago