Question

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution. (3, 1) and (-2, 3)

Answer 1

Answer: $2x+5y-1=0$

Step-by-step explanation:

The equation of a line passing through (a,b) and (c,d) is given by :_

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Then, the equation of a line passing through (3, 1) and (-2, 3) is given by :-

$(y-1)=\dfrac{3-1}{-2-3}(x-3)\\\\\Rightarrow\ (y-1)=\dfrac{2}{-5}(x-3)\\\\\Rightarrow\ -5(y-1)=2(x-3)\\\\\Rightarrow\ -5y-5=2x-6\\\\\Rightarrow\ 2x+5y-6+5=0\\\\\Rightarrow\ 2x+5y-1=0$

Hence, the equation of the kine in standard form = $2x+5y-1=0$

Answer 2

-2 -3 / 3 - 1

-5 / 2

So the slope of the points is -5/2, and I have no explanation other than I used to point slope formula.