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olga2289 [7]
3 years ago
7

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

er in the box provided or use the upload option to submit your solution. (3, 1) and (-2, 3)
Mathematics
2 answers:
bearhunter [10]3 years ago
8 0

Answer: 2x+5y-1=0

Step-by-step explanation:

The equation of a line passing through (a,b) and (c,d) is given by :_

(y-b)=\dfrac{d-b}{c-a}(x-a)

Then, the equation of a line passing through (3, 1) and (-2, 3) is given by :-

(y-1)=\dfrac{3-1}{-2-3}(x-3)\\\\\Rightarrow\ (y-1)=\dfrac{2}{-5}(x-3)\\\\\Rightarrow\ -5(y-1)=2(x-3)\\\\\Rightarrow\ -5y-5=2x-6\\\\\Rightarrow\ 2x+5y-6+5=0\\\\\Rightarrow\ 2x+5y-1=0

Hence, the equation of the kine in standard form = 2x+5y-1=0

alexandr402 [8]3 years ago
5 0

-2 -3 / 3 - 1

-5 / 2

So the slope of the points is -5/2, and I have no explanation other than I used to point slope formula.

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Is this thesis OK for my schizophrenia essay? Schizophrenia is a severe mental illness that deeply affects the patient's daily l
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I don't know how many paragraphs your professor needs you to develop, but if your essay consists on just 3 paragraphs (introduction, body and conclusion) your thesis is OK.
Now, if your essay needs to have, lets say 4 or 5 paragraphs (introduction, body 1, body 2, body 3, and conclusion) I'd recommend you to add two more details to your essay. For example,

Schizophrenia is a severe mental illness that deeply affects not only the patient's daily life, but also his family and friends.

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
lbvjy [14]

Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:

f(x)=[1 / (4p)] (x-h)^2+k

where Vertex: V=(h,k)

The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

h=(3+3)/2→h=6/2→h=3

k=(5+1)/2→k=6/2→k=3

Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

f(x)=[ 1 / (-8) ] (x-3)^2 + 3

f(x)= - (1/8) (x-3)^2 + 3

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3 years ago
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