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Anna11 [10]
2 years ago
10

Eric has $115 to spend on back to school clothes. So far, he has spent $90. Write an inequality to show how much more money Eric

can spend.
Mathematics
2 answers:
Tema [17]2 years ago
8 0

Answer:

Step-by-step explanation:

hi

madreJ [45]2 years ago
4 0

Answer:

Q1 answer below

Step-by-step explanation:

Eric has to spend $115 and he has spent $90. We need to know how much money he can spend, therefore:

Let x = the money he can now spend

90 + x ≤ 115

x ≤ 115 -90

x ≤ 25.

<h2>Please mark me as brainliest</h2>
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Step-by-step explanation:

y=55°(corresponding angles are equal)

x=55°(alternate angles are equal).

z+55°=180°

=180-55=z

z=125°

5 0
2 years ago
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Write the number 29085 in expanded form.​
Alex

Answer:

We expand a number to show the value of each digit.

29085:

20,000 + 9,000 + 000 + 80 + 5 = 29085

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3 years ago
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Evaluate (–1)8 + (–1)7 – 16 – 14 – (–1)2. Pay attention to the placement of the parentheses and negative signs. Question 1 optio
Inessa05 [86]
Since we are evaluating, we use PEMDAS so we know the order the operations. Follow PEMDAS:

Original Expression: (-1)8+(-1)7-16-14-(-1)2.

Evaluating: -8-7-16-14+2

-8-7=-15-16=-31-14=-45+2=-43.

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8 0
2 years ago
Need help with intreset
stiks02 [169]

Answer:

11%/ 0.11

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I=prt

154=700*x*2

154=1400x

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4 0
3 years ago
According to the American Lung Association, 7% of the population has lung disease. Of those having lung disease, 90% are smokers
postnew [5]

Answer:

Probability that a smoker has lung disease = 0.2132

Step-by-step explanation:

Let L = event that % of population having lung disease, P(L) = 0.07

So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93

S = event that person is smoker

% of population that are smokers given they are having lung disease, P(S/L) = 0.90

% of population that are smokers given they are not having lung disease, P(S/L') = 0.25

We know that, conditional probability formula is given by;

                        P(S/L) = \frac{P(S\bigcap L)}{P(L)}  

                        P(S\bigcap L) = P(S/L) * P(L)

                                      = 0.90 * 0.07 = 0.063

So,  P(S\bigcap L) = 0.063 .

Now, probability that a smoker has lung disease is given by = P(L/S)

      P(L/S) = \frac{P(S\bigcap L)}{P(S)}

P(S) = P(S/L) * P(L) + P(S/L') * P(L')

       = 0.90 * 0.07 + 0.25 * 0.93 = 0.2955

Therefore, P(L/S) = \frac{0.063}{0.2955} = 0.2132

Hence, probability that a smoker has lung disease is 0.2132 .

7 0
3 years ago
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