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3 years ago

2(x+5)=3x+1 ejekskkekwlwlwbebejkdkekehkekdjekkekrbrbfjndmdkdkebbe

Mathematics

1 answer:

LekaFEV [45]3 years ago

7 0

Answer:

x = 9

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(x+5)=3x+1

(2)(x)+(2)(5)=3x+1(Distribute)

2x+10=3x+1

Step 2: Subtract 3x from both sides.

2x+10−3x=3x+1−3x

−x+10=1

Step 3: Subtract 10 from both sides.

−x+10−10=1−10

−x=−9

Step 4: Divide both sides by -1.

yeah.

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3 years ago

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A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

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3 years ago

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Law Incorporation [45]

Answer:

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Step-by-step explanation:

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I hope it helps you!

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Answer:

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