Question

The supreme shipping company can load trucks with both rectangular and cylindrical containers. A rectangular container has a volume of 100 feet and weighs 200 pounds. Hey cylindrical container has a volume of 200 ft.³ cubed and weighs 100 pounds. Each truck has room for at most 4200 ft.³ of containers and can carry a maximum of 4800 pounds. If the shipping company charges $60 to ship a rectangular container and $55 to ship a cylindrical container how many of each should they ship to maximize their income

Answer 1

the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

Let x be the number of rectangular containers and y the number of cylindrical containers.

Since a rectangular container has a volume of 100 ft ³and weighs 200 pounds and a cylindrical container has a volume of 200 ft.³ and weighs 100 pounds, and each truck has room for at most 4200 ft.³ of containers and can carry a maximum of 4800 pounds,

We have that the maximum volume of the truck V = 100x + 200y.

Also, the maximum weight of the truck is W = 200x + 100y

Since V = 4200 ft.³  and W = 4800 pounds,

100x + 200y = 4200 and 200x + 100y = 4800

x + 2y = 42 (1) and 2x + y = 48 (2)

Multiplying (1) by 2 and (2) by 1, we have

2x + 4y = 84 (3) and 2x + y = 48 (4)

Subtracting (4) from (3), we have

2x + 4y = 84

-

2x + y = 48

3y = 36

y = 36/3

y = 12

Substituting y into (1), we have

x + 2y = 42

x + 2(12) = 42

x + 24 = 42

x = 42 - 24

x = 18

Also, since the shipping company charges $60 for a rectangular container and $55 for a cylindrical container, the income, P = 60x + 55y

Since x = 18 and y = 12, the maximum income is P = 60x + 55y

= 60(18) + 55(12)  

= 1080 + 660

= $1740

So, the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

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