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Reptile [31]
2 years ago
5

One million five hundred fifty eight thousand three hundred sixty-four numeral international system​

Mathematics
1 answer:
daser333 [38]2 years ago
8 0

Answer:

1,558,364 jabejbwjwbshhsjwbw

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I need to find sec(theta)= 2(sqrt3)/3
Sloan [31]

Answer: 30° and 330°

<u>Step-by-step explanation:</u>

sec θ = \frac{2\sqrt{3}}{3}

sec θ = \frac{1}{cos(\theta)}

\frac{1}{cos(\theta)} = \frac{2\sqrt{3}}{3}

cos θ = \frac{3}{2\sqrt{3}}

cos θ = \frac{3}{2\sqrt{3}}(\frac{\sqrt{3}}{\sqrt{3}})

cos θ = \frac{3\sqrt{3}}{3*2}

cos θ = \frac{\sqrt{3}}{2}

Look at the Unit Circle to see that cos = \frac{\sqrt{3}}{2} at 30° and 330°  ( which is equivalent to π/6 and 11π/6)


4 0
2 years ago
Read 2 more answers
Write each pair of quantities as a unit rate.
Ronch [10]
A) 75heartbeats per min
B) $9.35 per ticket
C) 2.25 per golf ball
D) $9.75 per hour
3 0
2 years ago
The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930.
andrey2020 [161]

Answer:

14 home runs

Step-by-step explanation:

This is basically a subtraction problem.

So the maximum number is 60 home runs in 1927.

The minimum number is 46 home runs in 1929.

So you subtract these 2 values.

60 - 46

= 14

So the maximum number exceed the minimum number with 14 home runs as the difference.

7 0
3 years ago
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Six less than the quotient of a number and two, increased by ten” when n = 8?
svp [43]

6 -(8  \times 2) + 10 = 20
6 0
3 years ago
Need answer to A and B!
Roman55 [17]

To find the probability of drawing certain colour of balls, we first need to find the total number of balls:

5 + 7 +5 = 17

<u>For the number of red balls that need to be added</u>

The original probability of drawing a red ball:

red ball/ total number of balls

= 5/17

To find the number of balls required, we can set an equation.

Let the number of red balls that need to be added be x.

5+x / 17+x = 5/6

(5+x) x 6 = (17+ x) x5

30 +  6x = 85 + 5x

6x - 5x = 85 - 30

x = 55

Therefore, <u>55</u> red balls need to be added.

<u>For the number of black balls that need to be added</u>

The original probability of drawing a white ball:

white ball/ total number of balls

=5/17

To find the probability required, we can set an equation.

Let the number of black balls that need to be added be y.

5/ 17 + y = 1/6

5 x 6 = 17 + y

30 = 17 + y

30 - 17 = y

y = 13

Therefore, <u>13</u> black balls need to be added.

Hope it helps!

5 0
3 years ago
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