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3 years ago

How do you calculate concrete weight per cubic yard?

1 answer:

6 0

Total weight = Volume × density

5) calculate weight of concrete slab by multiplying volume and their density in similar unit as Weight = Volume× density, density= 150lb/ cf, so total weight = 33 cf × 150 lb/cf = 4950 pounds or 2.475 short tons.

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Which shows zero as significant digits? Check all that apply.

melisa1 [442]

Answer:

Explanation:

0.02

0.604

70,230

becuase if you take away the 0 then it would change the value of the number

8 0

3 years ago

For a given force, if the mass of the object is doubled, its acceleration becomes ??

nekit [7.7K]

Force = Mass . Accelaration

f=ma

force is directly proportional to mass and accelaration

therefore when mass of the object is doubled, the accelaration would be halved

since

a=f/m

7 0

3 years ago

Read 2 more answers

What would be the resulting condition if Earth's axis was perpendicular to the Sun?

blagie [28]

Answer:

I belive it would be B or D, but B seems more likely

Explanation:

3 0

3 years ago

Read 2 more answers

At the same instant that a 0.50 kg ball is dropped from 25 m above Earth, a second ball, with a mass of .25 kg, is thrown straig

Anettt [7]

Answer:

A. 7.1m

B. 3.55m/s

C. 1.775m/s^2

Explanation:

First step is to identify given parameters;

Ball 1: m₁ = 0.5kg, u (initial velocity) =0, t = 2seconds

Ball 2: m₂ = 0.25kg, u = 15m/s, t = 2seconds

Second step: we determine the y-coordinate of ball 1 after 2 seconds, using the equation of motion under gravity as shown below;

$y = ut - \frac{gt^2}{2}$

$y_{1} = 0 X 2 - \frac{9.8 X2^2}{2}$

$y_{1} = -19.6m$

Recall, that the ball was thrown from a height of 25m, total y-coordinate of ball 1 after 2 seconds becomes 25m +(-19.6m)

[tex]y_{1} = 5.4m[/tex]

Third step: we determine the y-coordinate of ball 2 after 2 seconds

$y_{2} = 15 X 2 - \frac{9.8 X2^2}{2}$

$y_{2} = 10.4m$

Fourth step: we determine the y-component of the center mass of the two balls

$y = \frac{m_{1}y_{1} +m_{2}y_{2}}{m_{1} +m_{2} }$

$y = \frac{(0.5)X(5.4) +(0.25) X (10.4)}{(0.5 +0.25) }$

y = 7.1m

Fifth step: we solve B part of the question; velocity of the center mass of the two balls

$Velocity = \frac{distance of center mass of the two balls (y)}{time}$

$velocity = \frac{7.1 m}{2 s}$

velocity = 3.55m/s

Sixth step: we solve C part of the question; acceleration of the center mass of the two balls

$acceleration = \frac{velocity}{time}$

$acceleration = \frac{3.55}{2}$

acceleration = 1.775 m/s^2

7 0

3 years ago

A book is at rest on a table. According to Newton's first law of motion, which explanation best describes the reason why the boo

levacccp [35]

Answer:

I belive it is c

Explanation: If an object is at rest it shall stay at rest until an equal or oppisite force is applied.

8 0

4 years ago