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kati45 [8]
3 years ago
5

If a person driving 130 miles per hour and hit a brick wall ? Does the brick wall hit (push) the car back ? Which Newton laws wo

uld explain this accident and why ?
Physics
2 answers:
belka [17]3 years ago
8 0

An action of push or pull on an object is force. The two bodies interact with each other. Newton's third law of motion states that every action has equal and opposite reaction. This means that if an object A exerts F amount of force on another object B, object B would also exert the same amount of force on A. when a person driving at speed 130 miles per hour hits wall, the wall would also apply an equal force on car and that would cause the damage to it.  

Anuta_ua [19.1K]3 years ago
5 0

Answer#1  

Newton's third law of movement expresses that each activity has equivalent and inverse response. This implies if an item x applies F measure of power on another article y, object y would likewise apply a similar measure of power on x. at the point when an individual driving at speed 130 miles for each hour hits divider, the divider would likewise apply an equivalent power on vehicle and that would make the harm it.  

Answer #2  

Newton's third law of movement will be connected in this situation  

this law expresses that  

each activity has a response meet in sufficiency yet  opposite in indirection.  

This implies if an item state x applies F measure of power on another article y, object y would likewise apply a similar measure of power on x

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Ilia_Sergeevich [38]

Answer:

It is enough

Explanation:

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The two ways in which the performance coefficient can be expressed are given by:

COP_p = \frac{T_H}{T_H-T_L}

Where,

T_H =High Temperature

T_L = Low Temperature

And the other way is,

COP_p = \frac{\dot{Q}}{W}

Where \dot{Q} is heat rate and W the power consumed.

We have all our terms in Celsius, so we calculate the temperature in Kelvin

T_H = 22+273 = 295K

T_L = 2+273 = 275k

The rate at which heat is lost is:

\dot{Q} = 110000kJ/h

The power consumed by the heat pump is

\dot{W} = 5kW

And the coefficient of performance is

COP_p = \frac{T_H}{T_H-T_L}

COP_p = \frac{295}{295-275}

COP_p = 14.75

With this value we can calculate the Power required,

COP_p = \frac{\dot{Q}}{W}

14.75 = \frac{110000}{W}

W = \frac{110000}{3600*14.75}

W = 2.07kW

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Answer:

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3 0
4 years ago
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Answer:

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Y_Kistochka [10]

Answer:

Explained below.

Explanation:

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