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mafiozo [28]
3 years ago
6

Calculate the energy used by a 0.011 kW lightbulb in 1 minute. Use the formula: energy (J) = power (W) × time (s)

Physics
2 answers:
SIZIF [17.4K]3 years ago
8 0
The baser would be 660 do u need steps
nataly862011 [7]3 years ago
4 0

Answer:

660

Explanation:

0.011kW = 11W

energy = 11 x 60

            = 660J

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If the momentum of a 1000 kg car travelling at 10 m/s was transferred completely to a 20.0 kg traffic barrier, what would the fi
denis-greek [22]

Answer:

d. 500 m/s

Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

deduced from the question,

Momentum of the car = momentum of the barrier.

MV = mv ............................. Equation 1

Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

v = MV/m........................ Equation 2

Given: M = 1000 kg, V = 10 m/s, m = 20 kg.

Substitute into equation 2

v = 1000(10)/20

v = 500 m/s.

Hence the speed of the barrier = 500 m/s

The right option is d. 500 m/s

8 0
4 years ago
A. 6.084 x 103<br> B. 6.084 x 10-6<br> C. 6.084 x 10-3<br> O D. 6.084 x 106
Veseljchak [2.6K]

Answer:

A

Explanation:

I'm just guessing I'll be honest I don't know

5 0
3 years ago
12. A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of
Margaret [11]
1/2 m/s2
30 Na




I hope this helps!
4 0
3 years ago
What are two parts that make up a vector
mojhsa [17]

Answer:

Vectors have both magnitude and direction.

3 0
3 years ago
An electric lamp consumes 60W at 220 volts. How many dry cells of 1.5 V and internal resistance 1 Ohm are required to glow the l
GenaCL600 [577]

Answer:

1. Number of dry cells of 1.5 V required is 40.

2. Number of internal resistance of 1 ohm required is 807

Explanation:

We'll begin by calculating the resistance. This can be obtained as follow:

Power (P) = 60 W

Voltage (V) = 220 V

Resistance (R) =?

P = V²/R

60 = 220² / R

Cross multiply

60 × R = 220²

60 × R = 48400

Divide both side by 60

R = 48400 / 60

R ≈ 807 Ohm

1. Determination of the number of dry cells of 1.5 V required.

Voltage (V) = 220

Dry Cells = 1.5 V

Number of dry cells (n) =?

n = Voltage / Dry cells

n = 60 / 1.5

n = 40

2. Determination of the number of internal resistance of 1 ohm required.

Resistance (R) = 807 Ohm

Internal resistance (r) = 1 ohm

Number of internal resistance (n) =?

n = R/r

n = 807 / 1

n = 807

SUMMARY:

1. Number of dry cells of 1.5 V required is 40.

2. Number of internal resistance of 1 ohm required is 807

3 0
3 years ago
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