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lakkis [162]
3 years ago
15

Balancing Chemical Equations

Chemistry
2 answers:
slega [8]3 years ago
7 0

Answer:

1) 1 N2 + 3 H2  2 NH3

2) 2 KClO3  2 KCl + 3 O2

3) 2 NaCl + 1 F2  2 NaF + 1 Cl2

4) 2 H2 + 1 O2  2 H2O

5) 1 Pb(OH)2 + 2 HCl  2 H2O + 1 PbCl2

6) 2 AlBr3 + 3 K2SO4  6 KBr + 1 Al2(SO4)3

7) 1 CH4 + 2 O2  1 CO2 + 2 H2O

8) 1 C3H8 + 5 O2  3 CO2 + 4 H2O

9) 2 C8H18 + 25 O2  16 CO2 + 18 H2O

10) 1 FeCl3 + 3 NaOH  1 Fe(OH)3 + 3 NaCl

11) 4 P + 5 O2 2 P2O5

12) 2 Na + 2 H2O  2 NaOH + 1 H2

13) 2 Ag2O  4 Ag + 1 O2

14) 1 S8 + 12 O2  8 SO3

15) 6 CO2 + 6 H2O  1 C6H12O6 + 6 O2

16) 1 K + 1 MgBr  1 KBr + 1 Mg

17) 2 HCl + 1 CaCO3  1 CaCl2 + 1 H2O + 1 CO2

18) 1 HNO3 + 1 NaHCO3  1 NaNO3 + 1 H2O + 1 CO2

19) 2 H2O + 1 O2  2 H2O2

20) 2 NaBr + 1 CaF2  2 NaF + 1 CaBr2

21) 1 H2SO4 + 2 NaNO2  2 HNO2 + 1 Na2SO4

(RECTANGLES ARE ARROWS)

kati45 [8]3 years ago
3 0
Here is the answer to these equations.
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3 years ago
What would be the expected radius of a nucleus having 82 protons and 125 neutrons?
Luba_88 [7]

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5 0
2 years ago
What is the molarity of a solution containing 17.0 g of KCl in 213 mL of KCl solution?
Anarel [89]

Answer:

1.070MKCl

Explanation:

So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)

Since we do not have liters in this problem, we would need to convert  milliliters to liters

<u>213 mL= 0.213 L</u>

We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>

Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.

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M=0.228 mol/0.213L

M= 1.070MKCl

I know this was long, but I hope this helps (:

5 0
3 years ago
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