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vichka [17]
3 years ago
5

Baking soda (NaHCO3, 84.0 g/mol) requires acids from other ingredients to generate the carbon dioxide needed to make bread rise.

The following equation describes this reaction, where HB is some unspecified acid. If 20.4 g of baking soda are used in a recipe and enough acid is present for a complete reaction, how many moles of carbon dioxide are generated?
HB + NaHCO3 ⟶ H2O + CO2 + NaB
a. 0.243 mol
b. 0.204 mol
c. 0.334 mol
d. 0.232 mol
e. 0.464 mol
Chemistry
1 answer:
Rainbow [258]3 years ago
5 0
0.122283884747646362672 mol
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Find the mass of 0.235 moles of SiO2? (NOTE: use correct significant figures!)
marta [7]

Answer: 14.1g

Explanation:

Given that,

number of moles of SiO2 = 0.235 moles

Mass in grams = Z (let unknown value be Z)

Molar mass of SiO2 = ?

To get the molar mass of SiO2, use the atomic mass

Silicon = 28g;

Oxygen = 16g

i.e Molar mass of SiO2 = 28g + (16g x 2)

= 28g + 32g

= 60g/mol

Now, apply the formula

Number of moles = Mass / molar mass

0.235 moles = Z / 60g/mol

Z = 0.235 moles x 60g/mol

Z = 14.1 g

Thus, the mass of SiO2 is 14.1 grams.

8 0
3 years ago
What are the products in the equation for cellular respiration? A. Oxygen and lactic acid b. Carbon dioxide and water c. Glucose
Colt1911 [192]
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4 0
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A student did an experiment to determine the specific heat capacity of a metal alloy. The student put a sample of the alloy in b
guapka [62]

Answer:

a) ∆T=T1-T2

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Explanation:

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7 0
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7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken
Nana76 [90]

<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution.  The equation used to calculate molarity of the solution is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M

Hence, the molarity of Iron (III) chloride is 0.622 M.

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