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Lapatulllka [165]
3 years ago
15

During a running (dynamic) compression test at idle, a good engine should produce PSI. A. 150 to 200 B. 100 to 150 C. 30 to 60 D

. 60 to 90​
Chemistry
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

b

Explanation:

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What is the maximum number of electrons in an atom n=4 l=1 ml=0
Nitella [24]

Answer:

18 electrons

Explanation:

when l=1, this tell you that it is "p sub shell"

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3 years ago
Isopropyl alcohol is mixed with water to produce a 35.0 % (v/v) alcohol solution. How many milliliters of each component are pre
PilotLPTM [1.2K]

229.25 mL of isopropyl alcohol

425.75 mL of water

Explanation:

Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.

volume of  isopropyl alcohol = (35/100) × solution volume

volume of  isopropyl alcohol = 0.35 × 655 mL = 229.25 mL

Now, knowing the volume of isopropyl alcohol we can determine the volume of water.

volume of the solution = volume of isopropyl alcohol + volume of water

volume of water = volume of the solution - volume of isopropyl alcohol

volume of water = 655 mL - 229.25 mL = 425.75 mL

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percent by volume concentration

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3 0
3 years ago
If you pump air into cycle tyre a slight warming effect is noticed at valve stem why
SSSSS [86.1K]
Probably the kinetic energy of rubbing the pump against the valve, combined with the increase in gas pressure in the tire itself.
8 0
3 years ago
How many grams are in 1 mole of Pb3(PO4)4?
kvasek [131]

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2  .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 .  4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

6 0
3 years ago
Read 2 more answers
What is the volume if 1.5 mol of gas has a pressure of 700 torr at 15°C?
Tasya [4]

Answer:

V = 38.48 L

Explanation:

Given that,

No. of moles = 1.5 mol

Pressure, P = 700 torr

Temperature, T = 15°C = 288 K

We need to find the volume of the gas. The ideal gas equation is given by :

PV=nRT\\\\V=\dfrac{nRT}{P}\\\\V=\dfrac{1.5\times 62.36\times 288}{700}\\\\V=38.48\ L, R = L.Torr.K⁻¹.mol⁻¹

So, the required volume is equal to 38.48 L.

7 0
3 years ago
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