Name the substance that combines with water in photosynthesis

Carry out the following calculation. Express your answer in the correct number of significant figures.

77julia77 [94]

Answer:

43.1 g

Explanation:

Density, d is defined as the mass per unit volume of an object. Density is therefore expressed as

d=m/v

Here, m is mass and v is the volume

Making mass the subject of the formula

Mass, m=dv

The volume, v is given by

V=lwh

Substituting lwh for v in the equation for mass then mass, m=dlwh

Substituting 2.6 g/cm3 for d, 4.0 cm for l, 1.8 m for w and 2.3 for h then the mass of the block will be

M=2.6*4*1.8*2.3=43.056 g

Expressing it in 1 decimal place, mass is approximately 43.1 g

3 0

3 years ago

Jasmine makes a note card about series circuits. she records the points shown. a 2 column table with 1 row. the column on the le

Bess [88]

Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.

<h3>What is a parallel circuit?</h3>

A parallel circuit is a circuit in which the components are connected to a common junction. This implies that if one bulb goes out in a parallel connection, all the bulbs will go out.

As such, Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.

Learn more about parallel connection: brainly.com/question/12400458

#SPJ4

7 0

2 years ago

The rate at which work is done is also the definition of which of the following?

gregori [183]

B) Power
Because Power= Work/time

7 0

3 years ago

A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound

Vaselesa [24]

Answer:B)439.21 Hz

Explanation:

Given

velocity of train $v=120 km/h\approx 120\times \frac{5}{18}=33.33 m/s$

frequency of train $f_a=0.400 kHz\approx 400 Hz$

speed of sound $c=340 m/s$

frequency from Doppler effect can be calculated by

$f_a=(\frac{c}{c+v})\cdot f$

$400=(\frac{340}{340+33.33})\cdot f$

$400=\frac{340}{373.33}\cdot f$

$f=400\times 1.098$

$f=439.21 Hz$

5 0

3 years ago

A charge of −20 µC is distributed uniformly over the surface of a spherical conductor of radius 11.0 cm. Determine the electric

Alex73 [517]

Answer:

(a) $-6.76\times 10^{12}\ N/C$

(b) $-1.352\times 10^{13}\ N/C$

(c) $-7.2\times 10^{11}\ N/C$

Explanation:

(a)

Given:

Charge on sphere (Q) = $-20\ \mu C=-20\times 10^{-6}\ C$

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 5 cm = 0.05 m

Coulomb's constant (k) = $9\times 10^{9}\ Nm^2/C^2$

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

$E=(\frac{kQ}{R^3})r$

Plug in the given values and solve for 'E'. This gives,

$E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.05\\\\E_{in}=-1.352\times 10^{14}\times 0.05\\\\E_{in}=-6.76\times 10^{12}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)$

(b)

Given:

Charge on sphere (Q) = $-20\ \mu C=-20\times 10^{-6}\ C$

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 10 cm = 0.10 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

$E=(\frac{kQ}{R^3})r$

Plug in the given values and solve for 'E'. This gives,

$E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.10\\\\E_{in}=-1.352\times 10^{14}\times 0.10\\\\E_{in}=-1.352\times 10^{13}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)$

(c)

Given:

Charge on sphere (Q) = $-20\ \mu C=-20\times 10^{-6}\ C$

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 50 cm = 0.50 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r > R' from the center of sphere is given as:

$E=\dfrac{kQ}{r^2}$

Plug in the given values and solve for 'E'. This gives,

$E_{out}=(\frac{9\times 10^{9}\times -20}{(0.50)^2})\\\\E_{out}=-7.2\times 10^{11}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)$

8 0

4 years ago