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Serga [27]
3 years ago
13

The wave function for a particle must be normalizable because:________ a. the particle's angular momentum must be conserved. b.

the particle cannot be in two places at the same time. c. the particle must be somewhere. d. the particle's momentum must be conserved. e. the particle's charge must be conserved
Physics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

C the particle must be somewhere.

Explanation:

This is because normalization of wave function means the maximum probability of finding a particle in a region is 1. And a Wave function describes the probability of finding a particle in region. Also Since it is a probability distribution, its integral over all space must be 1, explaining that the probability that the particle is somewhere and thus it must integrate to 1, meaning it must be it must be normalizable

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Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


3 0
3 years ago
Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon
Nutka1998 [239]

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

T^2=\frac{4\pi}{GM}r^3

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min

the comet takes around 16.63min

8 0
3 years ago
a battery is connected to a resistor. as charge flows, the chemical energy of the battery is dissipated as _________.
balandron [24]

As charge flows, the chemical energy of the battery is dissipated as the time of charge flow increases.

Electric power is defined as the rate at which electric energy is dissipated.

The power of the current flowing through the circuit is calculated as follows;

P = IV

P = I x IR

P = I²R

where;

  • <em>P is the power dissipated</em>
  • <em>I is the current flowing in the circuit</em>
  • <em>R is the resistance of the circuit</em>

The electric energy is given as;

E = Pt

E = I²Rt

Thus, we can conclude that as charge flows, the chemical energy of the battery is dissipated as the time of charge flow increases.

Learn more here:brainly.com/question/21392880

5 0
3 years ago
Sources of vitamin C include all but
Anna11 [10]
I believe its coenzymes.
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3 years ago
What is the theory of super symmetry? a. The theory is the same as the conservation of energy. c. It states that for every parti
SVETLANKA909090 [29]
Fam I believe the answer..... is it states that for every particle found there is an identical "mirror" particle that is the same in every way except for spin
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4 years ago
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