Answer:
A)5524J,
B) 29.2Nm
Explanation:
This question can be treated using work- energy theorem
Work= change in Kinectic energy
W= Δ KE
Work= difference between the final Kinectic energy and intial Kinectic energy.
We know that
Kinectic energy= 1/2 mv^2 .............eqn(1)
This can be written in term of angular velocity, as
KE= 1/2 I
x = V<em>x</em> * t
given V<em>x</em> = 10m/s n t = 3.53s
x = 10 * 3.53
= 35.3m
The best and most correct answer among the choices provided by your question is the first choice or letter A.
Heat transfers associated with phase changes known as latent or "hidden" heats because h<span>eat absorbed or released in a phase change is measured in kJ while temperature is measured in °C.</span>
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Answer:1200
Explanation:
Given data
Upper Temprature
Lower Temprature 
Engine power ouput
Efficiency of carnot cycle is given by





rounding off to two significant figures

Answer:
Let me look up a couple of things regarding this question.
Explanation:
Then I will get back to you.