Answer:
Step-by-step explanation:
Divide: 3/13 = 3 ÷ 13
3/13 = 0.230769230769...
B) is your answer
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Answer:
4x^2 - 4x - 3
Step-by-step explanation:
f(x) = 2x - 1
g(x) = x^2 - 4
g(f(x)) = ?
[substitute the x of g(x) with f(x)]
g(x) = x^2 - 4
g(f(x)) = (2x - 1)^2 - 4
[solve]
[binomial * binomial = quadratic equation]
[use FOIL method (first, outer, inner, last)]
g(f(x)) = (2x - 1)(2x - 1) - 4
g(f(x)) = (2x*2x) + (-2x) + (-2x) + (1) - 4
[combine like terms]
g(f(x)) = 4x^2 - 2x - 2x + 1 - 4
g(f(x)) = 4x^2 - 4x - 3
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
A= π r2 and v=3.14d
---Volume(v=3.14d):
3.14(15) equals 47.1
47.1 rounds to 47
nearest hundreth would be 0 that rounds to .1 or .10,which rounds to 47
v=47
---Area(π r2)
3.14(7.5)^2 is 3.14(56.25)
176.625
176.625 rounded to the nearest hundreth is 176.630.
Answer:
The area of a circle with the diameter of 15 is 176.630.
