I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,




So, 

So, 
Hope this helps you!
So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19
red=19
blue=8
<h3><u>Question:</u></h3>
The perimeter of a rectangle is 34 units. Its width W is 6.5 units.
Write an equation to represent the perimeter in terms of the length L, and find the value of L
<h3><u>Answer:</u></h3>
The length of rectangle is 10.5 units
<h3><u>
Solution:</u></h3>
Given that,
Perimeter of rectangle = 34 units
Width of rectangle = 6.5 units
Let "L" be the length of rectangle
<em><u>The perimeter of rectangle is given by formula:</u></em>
Perimeter = 2(length + width)
<em><u>Substituting the values we get,</u></em>

Thus the equation is found
<em><u>Solve for "L"</u></em>

Thus length of rectangle is 10.5 units
Answer:
Step-by-step explanation: