<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
<em />
Answer:
I believe the median is 21
hope this helps
Q+12-2q+44=0
-q=-44-12
q=56
Answer:
<h2>
width = 3 feet</h2>
Step-by-step explanation:
Let h be the height of the door
and w be its width
The statement “The height of the door is I foot more than twice its width”
can be translated mathematically like this : h = 2w + 1
Let’s solve the equation for w:
h = 2w + 1
⇔ 2w = h - 1
now , if the door is 7 feet high then it’s width is equal to :
Answer:
a. 20
Step-by-step explanation:
just multiply 5 and $4 by 4
