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REY [17]
2 years ago
11

Is this correct? helppp​

Mathematics
2 answers:
Marta_Voda [28]2 years ago
8 0

Answer:

Yes its correct the unhighlighted is complement

Scilla [17]2 years ago
3 0

Answer:

maybe?

Step-by-step explanation:

i think its correct let me know if is not correct :)))

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Write the polynomial as a product: p^2q+r^2–pqr–pr<br> Thanks so much! Love you all who help!
Anarel [89]
Factor the equation so... 
(r^2-pr) and (p^2q-pqr)

Factor out (r^2-pr) = r(r-p)
Factor out (p^2q-pqr) = pq(p-r)

Add a negative to r(r-p) to make it -r(p-r)

(pq-r)(p-r) is the answer...  I'm sorry I can't explain things well, but I tried.
5 0
3 years ago
Question 10 (5 points)
11Alexandr11 [23.1K]
I think the answer is A
3 0
3 years ago
Read 2 more answers
Rigid transformations how to know when a figure is dilation transformation, rotation and dilation?​
Naddika [18.5K]

Answer:

the shape could be congruent or similar to its preimage. There are basically four types of transformations: Rotation; Translation; Dilation; Reflection; Definition of Transformations. Transformations could be rigid (where the shape or size of preimage is not changed) and non-rigid (where the size is changed but the shape remains the same).

Step-by-step explanation:

7 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Which is the soluction of x/5 - 10 = 20?<br>A x = 2 <br>B x = 6<br>C x = 50<br>D x = 150
ololo11 [35]

x/5 - 10 = 20

add 10 to each side

x/5 = 30

multiply by 5

x = 150


7 0
3 years ago
Read 2 more answers
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