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eduard
3 years ago
6

In Oakland County the fine for speeding is $15 for each mile per hour over the speed limit. Jim was fined $165 for speeding in a

25-mph zone. How fast was Jim going? Your answer​
Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

36 mph

Step-by-step explanation:

First, we have to find the unit rate of the money.

Since it's 15 dollars for each mile over the speed limit, divide 15 by 165.

The answer is 11, which means he was going 11 mph over the speed limit.

Add 11 to 25, and you get 36

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Pls anwers the question pls it has pictures as well pls pls pls pls pls pls pls
azamat

Answer:

a = $80.3

b = $80

c = 4

d = 16

e = 4

f = 88

g = $132

h = 33%

i = 6

j = 30

k = 21

l = $90

m = $36

o = 21/50

p = 105

q = 7

r = 8 cm

s = 2.4

t = 4

u = 400cm

v = $280

Step-by-step Explanation:

==>Increasing $72 by 10% to get a

a = 110% of $72 = 110% × $73

a = 1.1 × 73

a = $80.3

==>a ($80.3) rounded to the nearest 10 to find b = $80

b = $80

==>Writing b (80) as the product of its primes I.e.

b = 2^{c} * 5

Thus, 80 = 2⁴ * 5

c = 4

==>Calculating c² = d

d = 4² = 16

d = 16

==> ²/8 of d = e

e = ²/8 × 16

e = 2 × 2

e = 4

==> e% of 2200 = f

f = 4% × 2200

f = 0.04 × 2200

f = 88

==>Converting £f to $ = g

If £1 = $1.5,

£88 = $g

1 × g = 1.5 × 88

g = $132

==> Converting \frac{g}{400} into % = h%

h = 132÷400 ×100

h = 0.33 × 100

h = 33%

==> √(h + 3) = i

i = √(33 + 3)

i = √36

i = 6

==> i × (3 + 2) = j

j = 6 × (3 + 2)

j = 6 × 5

j = 30

==> j% of 70 = k

k = j% × 70

k = 30% × 70

k = 0.3 × 70

k = 21

==> If k bottles = $63, 30 bottles = $l

21 bottles = $63

30 bottles = $l

21 × l = 63 × 30

21l = 1,890

l = 1,890/21

l = $90

==>If Tim and Mike (m) shares $90 in the ratio 3:2, Mike (m) would receive thus:

⅖ × $90 = m

m = 0.4 × 90

m = $36

==> √m + m = n

n = √36 + 36

n = 6 + 36

n = 42

==>Converting n% to fraction = o

Thus, o = 42/100

o = 21/50

==> o of 250 = p

p = 21/50 × 250

p = (21 × 250)/50

p = 21 × 5

p = 105

==> expressing p as a product of its primes i.e. p = 3 × 5 × q

105 = 3 × 5 × 7

Therefore, q = 7

==> Given a rectangle with dimensions of q cm and r cm, with an area of 56cm². Let's find r.

Area of rectangle = length × width = q × r

Area = 56 cm²

q = 7 cm

r = ?

56 = 7 × r

56/7 = r

8 = r

r = 8 cm

==> r × 0.3 = s

s = 8 × 0.3

s = 2.4

==> s ÷ 0.6 = t

t = 2.4 ÷ 0.6

t = 4

==> If t is in meters, converting t to cm will give us u

Since 1m = 100cm

4m = u cm

1 × u = 100 × 4

u = 400cm

==> Vikki (v) and John shares $u in the ratio 7:3. Thus, Vikki (v) would receive the following:

v = ⁷/10 × $400

v = 0.7 × 400

v = $280

8 0
3 years ago
Can someone please help me on these two questions tysm
Rashid [163]
Plug them in:

x + 5y = 18 
x - 3y = 10

F. (1,13)
G. (13,1)
H. (-2,4)
J. (-2,-4)

1 + 5*13 = 18 is obliviously not true so that takes out the first option.
 
13 + 5*1 = 18 : This is true but we have to check the next one.
13 - 3*1 = 10 : This is also true so we know this is the answer. We don't really need to check the other 2 but u can if u want to.

Hope that helped :) <span />
8 0
2 years ago
Natalie was given a 30 question test. For each correct question she answered, she earned 2 points. For every incorrect answer sh
RideAnS [48]
T<span>he number of questions Natalie answered incorrectly.</span>
8 0
3 years ago
Can anyone answer this question with showing work <br> 532.6 • 8.53
MAVERICK [17]

The answer is: 4543.078

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%201%7D%7B2x%20-%201%7D%20%20-%20%20%5Cfrac%7Bx%20-%201%7D%7B2x%20%2B%201%
lubasha [3.4K]

x=0

because you must

determine the undefined range

write all numerators above the common denomonator

multiply the parenthesis

collect the alike terms

remove parenthesis

eliminate the opposites collect the like terms

set the numerator equal to 0

divide both sides by 6

check if thesolution is the defined range

if so then you would find your answer X=0

8 0
2 years ago
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