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barxatty [35]
3 years ago
6

Here is a triangle:

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0

Answer:

a.) 130°

b.) 70°

Step-by-step explanation:

For a given triangle

<h2>a.)</h2>

The sum of all angles on a straight line is equal to 180°

Now,

50° + a = 180°

Subtract 50° from each side we get,

50° - 50° + a = 180° - 50°

a = 130°

Thus, The size of the angle marked a is 130°

<h2>b.)</h2>

The sum of all angles in a triangle is equal to 180°

Now,

b + 50° + 60° = 180°

b + 110° = 180°

Subtract 110° from both side we get,

b + 110° - 110° = 180° - 110°

b = 70°

Thus, The size of the angle marked b is 70°

<u>-TheUnknownScientist</u><u> 72</u>

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


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