Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
84 is what you get when you add them
14 is what you get when you factor their GCF then add
hope this helps plz mark brainliest
Answer:
=b/a^4
Step-by-step explanation:
Remember: 50% means 1/2. So, if 18 is 50%, or 1/2, of a number, the number must be double 18.
18 x 2 = 36
18 is 50% of 36.
9514 1404 393
Answer:
sin(D) = cos(E) = (√3)/2
cos(D) = sin(E) = 1/2
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relationships between trig functions and right triangle sides.
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
For this diagram, this means ...
sin(D) = cos(E) = (13√3)/26 = (√3)/2
cos(D) = sin(E) = 13/26 = 1/2
