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2 years ago

Find the Domain and Range of the following: (6.-1) (-2.2) (18,-1) (-2,3) Domain: Range: Is this relation a function?

Mathematics

1 answer:

zheka24 [161]2 years ago

8 0

Answer:

Domain: {-2,6,18}

Range: {-1,2,3}

This relation is not a function.

Step-by-step explanation:

The domain is all of the x values given listed in order from least to greatest and not repeating any numbers. The range is the same thing, but with the y values given. This is not a function because multiple ordered pairs have more than one output for the input. Let's take -2 in these ordered pairs. It has two different outputs, 3 and 2. Because of this, it is not a function.

Hope this helps!!

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The answer is 52

x - the number of students in a bus

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10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

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Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

$p = \frac{4}{6} = 0.6667$

10 normal six sided dice are thrown.

This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

0.2992 = 29.92% probability of obtaining at least 8 failures.

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3 years ago

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damaskus [11]

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2 years ago

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The distance in kilometers in scientific notation $2.03 \times 10^3 km$

<h3>Scale factors</h3>

Scale factors are values or constants multiplied with a variable

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Hence the distance in kilometers in scientific notation $2.03 \times 10^3 km$

Learn more on distance here: brainly.com/question/23848540

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2 years ago

Find the Domain and Range of the following: (6.-1) (-2.2) (18,-1) (-2,3) Domain: Range: Is this relation a function?​

Find the Domain and Range of the following: (6.-1) (-2.2) (18,-1) (-2,3) Domain: Range: Is this relation a function?