X=31, the other post justifies, I just wanted to make it more accessible for if someone just needs the answer :)
Answer:
It might be 70 because 5m has the volume of 50 m so maybe 7m in volume is 70?
<h2>
Answer:</h2>
Option: A is the correct answer.
A. Two students are the same age but have different heights.
<h2>
Step-by-step explanation:</h2>
The height of a student could not be a function of the ages of a student because two or more students with the same age may have the different heights .
This means that a value on a x-axis (i.e. age) is mapped to two or more values i.e. corresponding y-value ( i.e. different heights) which violates the definition of function.
Hence, option: A is the correct answer.
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
Answer:
the real solutions are the ones that actually cross the x-axis.
so the real solutions are (-5, 0) (-1,0) (4,0) and (8,0)
