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BaLLatris [955]
3 years ago
6

Write an equation in standard form for the line that has slope 1/3 and passes through (-2, 8)

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

<h2>         -x + 3y = 26            </h2>

Step-by-step explanation:

The equation of a line which passes through <em>(x₁, y₁)</em> and with slope of <em>m</em> in point-slope form:

                              y - y₁ = m(x - x₁)

m = ¹/₃

(-2, 8)    ⇒   x₁ = -2,  y₁ = 8

Therefore,  the equation of the line which passes through (-2, 8) and with slope of 1/3 in point-slope form:

y - 8 = ¹/₃(x - (-2))

y - 8 = ¹/₃x + ²/₃                   {multiply both sides by 3}

3y - 24 = x + 2                    {subtract x from both sides}

-x + 3y - 24 = 2                     {add 24 to both sides}

-x + 3y = 26

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