Answer:
The first one perimeter is 111
Step-by-step explanation:
How to find the perimeter is too add all the numbers you see
Answer:
The company should use a mean of 12.37 ounces.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.
This means that ![\sigma = 0.17](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.17)
The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?
This is
, considering that when
, Z has a p-value of
, so when
.
Then
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![-2.17 = \frac{12 - \mu}{0.17}](https://tex.z-dn.net/?f=-2.17%20%3D%20%5Cfrac%7B12%20-%20%5Cmu%7D%7B0.17%7D)
![12 - \mu = -2.17*0.17](https://tex.z-dn.net/?f=12%20-%20%5Cmu%20%3D%20-2.17%2A0.17)
![\mu = 12 + 2.17*0.17](https://tex.z-dn.net/?f=%5Cmu%20%3D%2012%20%2B%202.17%2A0.17)
![\mu = 12.37](https://tex.z-dn.net/?f=%5Cmu%20%3D%2012.37)
The company should use a mean of 12.37 ounces.
Answer:
D
Step-by-step explanation:
Subtract $50 from $62.50
62.50 - 50 = 12.5