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3 years ago

Which relationship is NOT a function?

Mathematics

1 answer:

Vlad [161]3 years ago

8 0

Answer:

Option 1

Step-by-step explanation:

Functions cannot have two points with the same x-value or in this case, value on the left side. This means it must be the first option. This is because of how in the second option, each shape on the right matches with a different shape on the left. In option three, each number on the left matches to a different number on the right. This is the same with option four.

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3 years ago

Solve for y.

RideAnS [48]

Answer:

2nd Bullet point / (B)

Step-by-step explanation:

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2 years ago

Which expressions are equivalent?

KIM [24]

Answer:

first one

Step-by-step explanation:

Because the coefficient of x is 3 and coefficient of y is-7

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A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r

ohaa [14]

Answer:

$b=2\frac23\:\sf ft$

Area of triangle = 4 ft²

Area of rectangle = $6\frac23\: \sf ft^2$

Area of irregular figure = $10\frac23\: \sf ft^2$

Step-by-step explanation:

$\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}$

$\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}$

$\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}$

$\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}$

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2 years ago

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Mademuasel [1]

The best answer would be be C.20

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3 years ago