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2 years ago

Use the distributive property 4x13 Find the productI NEED HELP PLEASE!

Mathematics

1 answer:

Leviafan [203]2 years ago

4 0

4(10+3)
40+12
52

Mark brainliest please

Hope this helps you

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Helpp please!! 10 points

Zolol [24]

Slope is 1.3

take your 2 points and make a triangle, then count the small boxes to the point in the middle where they met. ( REMEMBER THE X&Y RULES)
you should get 4/3, you need to divide and put it into decimal form.
GOOD LUCK! :))

8 0

3 years ago

A trampolinist steps off from 15 feet above ground to a trampoline 13 feet below. The function h (t) = -16 t 2 + 15, where t rep

kondor19780726 [428]

Answer:

Trampolinist will land on the trampoline after 0.9 seconds.

Step-by-step explanation:

The function h(t) = -16t² + 15 represents the relation between height 'h' above the ground and the time 't' of the trampolinist.

We have to find the time when trampolinist lands on the ground.

That means we have to find the value of 't' when h(t) = 15 - 13 = 2

[Since trampoline is 2 feet above the ground]

When we plug in the value h(t) = 2

2 = -16t² + 15

2 + 16t² = -16t² + 16t² + 15

16t² + 2 = 15

16t² + 2 - 2 = 15 - 2

16t² = 13

$\frac{16t^{2}}{16}=\frac{13}{16}$

$t^{2}=\frac{13}{16}$

t = $\sqrt{\frac{13}{16}}$

t ≈ 0.9 seconds

Therefore, trampolinist will land on the trampoline at 0.9 seconds.

5 0

2 years ago

Solve for x:<br><br>5/7 = 4x/83

Simora [160]

Step-by-step explanation:

$\to \dfrac{5}{7} = \dfrac{4x}{83}$

By cross multiplication,

→ 83(5) = 4x(7)

→ 415 = 28x

In decimal : 14.8214286

7 0

3 years ago

Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

$\implies v=30, v=-9$

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0

2 years ago

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What is the exterior angle of a 20-gon

sertanlavr [38]

I believe it is 18 degrees ^-^

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3 years ago

Read 2 more answers